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Natasha_Volkova [10]
2 years ago
8

Which is larger 1/12 or 2 ounces

Mathematics
1 answer:
Alex17521 [72]2 years ago
6 0

The answer would be 2 ounces

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I’m not sure if I got the answer right and I need help on the table I’m lost
harkovskaia [24]

The given information permits us to calculate the circumference (C) of the wheel as follows

C=\frac{265}{5}=53in

Then (as you said correctly!) the same wheel will move

(53in)\cdot16=848in

after 16 rolls.

3 0
9 months ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. men the same
Serjik [45]
The number of standard deviations from the mean for a man 72 inches tall is
  Z = (72 -69.3)/2.8 ≈ 0.964
3 0
3 years ago
A vase contains 7 red flowers, 3 white flowers, and 5 yellow flowers. If George selects a flower from the vase for his wife, wha
gtnhenbr [62]

Answer:

The answer to your question is: P(A) = 0.47

Step-by-step explanation:

Data

7 red flowers

3 white flowers

5 yellow flowers

Probability  that he select a red one

Formula

 P(A) = Number of favorable cases of A / total number of outcomes

Number of favorable cases = 7

Total number of outcomes = 7 + 3 + 5 = 15

Substitution

                      P(A) = 7 / 15

                      P(A) = 0.47

4 0
3 years ago
-6+x/x^4 limit at x →0
Jlenok [28]

Answer:

not existing

Step-by-step explanation:

\frac{ - 6 + x}{ {x}^{4} }

lim x goes to 0 is

\frac{ - 6 + 0}{ {0}^{4} }  =   \frac{ - 6}{0}

so not exist

I'm not sure if u mean that or this

7 0
2 years ago
The speed of a runner increased steadily during the first two seconds of a race. Col1 Time (Sec) 0 0.5 1 1.5 2 Col2 Speed (ft/se
UkoKoshka [18]

Answer:

The distance is D. 21.25 ft.

Step-by-step explanation:

This is an example of a distance problem: <em>Find the distance traveled by an object during certain time period if the velocity of the object is known at all times.</em>

We are given a table of values for time and speed

\left\begin{array}{cccccc}t(sec)&0&0.5&1&1.5&2\\Speed (ft/sec)&0&5.1&9.3&12.5&15.6\end{array}\right

If the speed remains constant, then the distance problem is easy to solve by means of the formula

                                          distance = speed x time

Therefore, the total distance is

distance = 5.1\cdot 0.5+9.3\cdot 0.5+12.5\cdot 0.5+15.6\cdot 0.5\\distance = 21.25 \:ft

7 0
2 years ago
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