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makkiz [27]
2 years ago
5

Why do you think there are many wind systems between a pole and the equator instead of just one large single wind system

Chemistry
1 answer:
Crazy boy [7]2 years ago
4 0

As a result, the Poles have high pressure (cold air) while the Equator has low pressure (warm air). Hot air from the Equator rises and goes toward the Poles, while colder air from the Poles lowers and moves toward the Equator, resulting in a continuous wind pattern.

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The molar mass of Cr(OH)2 is:
son4ous [18]

The molar mass of Cr(OH)_2 is 86.02 g/mole .

<h3><u> Explanation:</u> </h3>

The molar mass of a chemical compound is represented as the mass of a unit of that compound separated by the number of substances in that unit, measured in moles. The molar mass is a volume, not molecular, the property of a substance.

The molar mass is a percentage of various examples of the compound, which usually change in mass due to the appearance of isotopes.

From the below attached table, the Molar mass of Cr(OH)_2 is 86.0108 g/mol.

3 0
3 years ago
Use bond energies to calculate the enthalpy of reaction for the combustion of ethane. Average bond energies in kJ/mol C-C 347, C
ivanzaharov [21]

The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.

The reaction is:

2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O  (1)  

The enthalpy of reaction (1) is given by:

\Delta H = \Delta H_{r} - \Delta H_{p}   (2)

Where:

r: is for reactants

p: is for products

The bonds of the compounds of reaction (1) are:

  • 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
  • 7O₂: 7 moles of 1 O=O bond  
  • 4CO₂: 4 moles of 2 C=O bonds  
  • 6H₂O: 6 moles of 2 H-O bonds

Hence, the enthalpy of reaction (1) is (eq 2):

\Delta H = \Delta H_{r} - \Delta H_{p}

\Delta H = 2*\Delta H_{CH_{3}CH_{3}} + 7\Delta H_{O_{2}} - (4*\Delta H_{CO_{2}} + 6*\Delta H_{H_{2}O})      

\Delta H = 2*(6*\Delta H_{C-H} + \Delta H_{C-C}) + 7\Delta H_{O=O} - (4*2*\Delta H_{C=O} + 6*2*\Delta H_{H-O})  

\Delta H = [2*(6*413 + 347) + 7*498 - (4*2*799 + 6*2*467)] kJ/mol  

\Delta H = -2860 kJ/mol          

Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.

Read more here:

brainly.com/question/11753370?referrer=searchResults  

I hope it helps you!        

7 0
2 years ago
How many protons, neutrons, and electrons are contained in uranium-238?
monitta
It has 92 protons, 92 electrons, and 238 — 92 : 146 neutrons.
8 0
3 years ago
Is a computer screen energy transfer or transformation?
yarga [219]
A computer screen is energy transfer
4 0
3 years ago
What does the term division of labor mean as it relates to cells?
lidiya [134]

Answer:

what each cells job is divided

Explanation:

7 0
3 years ago
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