<u>Answer:</u> The solubility product of silver (I) phosphate is 
<u>Explanation:</u>
We are given:
Solubility of silver (I) phosphate = 1.02 g/L
To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:
Molar mass of silver (I) phosphate = 418.6 g/mol

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.
The chemical equation for the ionization of silver (I) phosphate follows:
3s s
The expression of
for above equation follows:

We are given:

Putting values in above expression, we get:

Hence, the solubility product of silver (I) phosphate is 
Answer:
The proton gradient produced by proton pumping during the electron transport chain is used to synthesize ATP. Protons flow down their concentration gradient into the matrix through the membrane protein ATP synthase, causing it to spin (like a water wheel) and catalyze conversion of ADP to ATP.
The atomic mass is greater than the atomic number.
Answer:
0.1739
Explanation:
0.800 mol of N2
0.200 mol of H2
0.150 mol of CH4
Total moles of the mixture = 0.8 + 0.2 + 0.150 = 1.150 mol
Mole fraction of H2 = Number of moles of H2 / Total moles
Mole Fraction = 0.2 / 1.150 = 0.1739