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Inga [223]
3 years ago
10

Pleaseeeeee yelp!!! 100 points

Chemistry
1 answer:
Lilit [14]3 years ago
3 0

Answer:

The answer would be B the temperature of the juice was the temperature of the surrounding air...trust me lolllllllllllllllll

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A sealed helium balloon with an internal pressure of 1.00 atm and a volume of 4.50 L at 293 K is moved. What volume will the bal
bixtya [17]

Answer:

6.48 L

Explanation:

From the question,

Applying

PV/T = P'V'/T'......................... Equation 1

P = initial pressure of the helium balloon, V =  Initial volume of the balloon, T = Initial temperature of the balloon, P' = Final pressure of the balloon, T' = Final temperature of the balloon, V' = Final volume of the balloon.

make V' the subject of the equation

V' = PVT'/P'T......................... Equation 2

Given: P = 1 atm, V = 4.5 L, T' = 253 K, T= 293 K, P' = 0.6 atm

Substitute these values into equation 2

V' = (4.5×1×253)/(0.6×293)

V' = 1138.5/175.8

V' = 6.48 L

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3 years ago
HELP! WILL MARK BRAINLIEST! ASAP!!
lilavasa [31]

Answer:

Mn is a Paramagnetic

Explanation:

8 0
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Sedimentary rocks are described as small pieces of rock and animal remains that are weathered, swept downstream and then settle,
tangare [24]

A. True

Sedimentary rocks are the only rocks that can hold fossils.

7 0
3 years ago
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How many minutes are in 17 years?
Anarel [89]

Explanation:

8935200 mins plzzzźzzz mark it brainest

3 0
3 years ago
How do you solve this problem
ad-work [718]

Answer: Volume of gas in the stomach, V = 0.0318L or 31.8mL

Explanation:

The number of moles of oxygen will remain constant even though the liquid oxygen will undergo a change of state to gaseous inside the person's stomach due to an increase in temperature.

<em>Number of moles of oxygen gas = mass/molar mass</em>

molar mass of oxygen gas = 32 g/mol

mass of oxygen gas = density * volume

mass of oxygen gas = 1.149 g/ml * 0.035 ml

mass of oxygen gas = 0.040215 g

Number of moles of oxygen gas = 0.0402 g/(32 g/mol)

Number of moles of oxygen gas = 0.00125 moles

<em>Using the ideal gas equation, PV=nRT</em>

where P = 1.0 atm, V = ?, n = 0.00125 moles, R = 0.082 L*atm/K*mol, T = (37 + 273)K = 310 K

<em>V = nRT/P</em>

V = (0.00125moles) * (0.082 L*atm/K*mol) * (310 K) / 1 atm

V = 0.0318L or 31.8mL

3 0
3 years ago
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