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3 years ago

How many atoms of group 17 element would be needed react with one atom of a group 2 element? Explain

2 answers:

5 0

2 atoms of group 7 elements, because group 2 elements have 2 valence electrons and group 7 need just one atoms to stabilize.

shusha [124]3 years ago

3 0

Only one atom because atom with 17 electrons need that one electron to become stable

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Help Tell me the answer.

Paladinen [302]

Answer:

it's easy u just have to put them in a calculator the way they are it will give you your answer atleast I think so hope this helps

5 0

2 years ago

9. Axon and dendrites are both parts of a neuron. How is the role of axons different than the

musickatia [10]

Dendrites receive information from other sources while axons send information away from the neuron.

5 0

3 years ago

An atom of sodium can transfer its one valence electron to an atom of...

diamong [38]

Answer: Either give off or gain electrons to make a total of 8

8 0

2 years ago

An atom of 125Sn has a mass of 124.907785 amu. Calculate the binding energy in MeV per atom. Use the masses: mass of 1H atom = 1

Ksenya-84 [330]

Answer:

1.06×10³ MeV/atom

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Also, atomic number of Sn = 5 0

Thus, the number of protons = 50

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

125 = 50 + Number of neutrons

Number of neutrons = 75

Mass of neutron = 1.008665 amu

Mass of proton = 1.007825 amu

Calculated mass = Number of protons*Mass of proton + Number of neutrons*Mass of neutron

Thus,

Calculated mass = (50*1.007825 + 75*1.008665) amu = 126.041125 amu

Given mass = 124.907785 amu

<u>Mass defect = Δm = |126.041125 - 124.907785| amu = 1.13334 amu </u>

The conversion of amu to MeV is shown below as:-

1 amu = 931.5 MeV

<u>So, Energy = 1.13334*931.5 MeV/atom = 1.06×10³ MeV/atom</u>

3 0

3 years ago

An enzyme is discovered that catalyzes the chemical reaction SAD ↔ HAPPY A team of motivated researchers sets out to study the e

Pepsi [2]

Answer:

The $K_{m}$ of a substrate will be "10 μM".

Explanation:

The given values are:

$E_{t} = 20 \ nM$

$[Substract] = 40 \ \mu M$

$K_{cat}=600 \ s^{-1}$

Reaction velocity, $Vo=9.6 \ \mu M s^{-1}$

As we know,

⇒ $Vo=\frac{K_{cat}[E_{t}][S]}{K_{m}+[S]}$

On putting the estimated values, we get

⇒ $9.6=\frac{600\times 20\times 10^{-3}\times 40}{K_{m}+40}$

⇒ $K_{m}+40=\frac{600\times 20\times 10^{-3}\times 40}{9.6}$

⇒ $K_{m}+40=50$

On subtracting "40" from both sides, we get

⇒ $K_{m}+40-40=50-40$

⇒ $K_{m}=10 \ \mu M$

6 0

3 years ago