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3 years ago

How can u change cm to dm

Chemistry

2 answers:

Sophie [7]3 years ago

8 0

1 Decimeter (dm) is equal to 10 centimeters (cm).

So, divide the length value by 10

Elena-2011 [213]3 years ago

4 0

Answer:

Hello There!!

Explanation:

1 centimetre=0.1 decimetre so you divide it by 10.

hope this helps,have a great day!!

~Pinky~

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GalinKa [24]

Answer:

Explanation:

Matter is anything that has weight and occupies space. Weight is synonymous to mass

3 0

3 years ago

T/F___ At the eutectic composition, an alloy can solidify at a constant temperature.___ For effective dispersion strengthening,

azamat

Answer:

TRUE
FALSE
TRUE
FALSE
FALSE
TRUE

Explanation:

At the eutectic composition, an alloy can solidify at a constant temperature : TRUE . this is because at eutectic composition the type of reaction that takes place there is invariant reaction in its thermal equilibrium
For effective dispersion strengthening, the dispersed phase should be needle-like, as opposed to round : FALSE. because the rounded shape will not cause a crack.
Intermetallic compounds are usually hard and brittle : TRUE. because Intermetallic compounds prevents dislocation movements and this makes them brittle and hard
For the effective dispersion and strengthening, the dispersed phase should be continuous : FALSE. this is because the dispersed precipitate must be small and not continuous
Stoichiometric intermetallic compounds exist over a range of compositions : FALSE
Faster solidification results in smaller interlamellar spacing : TRUE

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2 years ago

Please select the word from the list that best fits the definition

AveGali [126]

Answer:

I choose D option because may be it's correct

3 0

2 years ago

Read 2 more answers

Which statement is true about magnetic poles

Ahat [919]

A. all magnets have two poles

5 0

3 years ago

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Consider this reaction 2Mg(s)+O2(g) ———> 2MgO(s) What volume (in milliners) of gas is required to react with 4.03 g Mg at STP

nydimaria [60]

The volume of a gas that is required yo react with 4.03 g mg at STP is 1856 ml

calculation/

calculate the moles of Mg used

moles=mass/molar mass

moles of Mg is therefore=4.03 g/ 24.3 g/mol=0.1658 moles

by use of mole ratio of Mg:O2 from the equation which is 2:1

the moles 02=0.1679 x1/20.0829 moles

at STP 1 mole of a gas= 22.4 l

0.0895 moles=? L

by cross multiplication

=0.0895 moles x22.4 l/ 1 mole=1.8570 L

into Ml = 1.8570 x1000=1856 ml approximately to 1860

6 0

3 years ago