Answer:
The new temperature of the water bath 32.0°C.
Explanation:
Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)
Initial temperature of the water = ![T_1=33.9^oC=33.9+273K=306.9 K](https://tex.z-dn.net/?f=T_1%3D33.9%5EoC%3D33.9%2B273K%3D306.9%20K)
Final temperature of the water = ![T_2](https://tex.z-dn.net/?f=T_2)
Specific heat capacity of water under these conditions = c = 4.18 J/gK
Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J
( 1kJ=1000 J)
![Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T%3Dm%5Ctimes%20c%5Ctimes%20%28T_2-T_1%29)
![-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)](https://tex.z-dn.net/?f=-69.0%5Ctimes%201000%20J%3D8100%20g%5Ctimes%204.18%20J%2Fg%20K%5Ctimes%20%28T_2-306.9%20K%29)
![-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)](https://tex.z-dn.net/?f=-69%2C000.0%20J%3D8100%20g%5Ctimes%204.18%20J%2Fg%20K%5Ctimes%20%28T_2-306.9%20K%29)
![T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC](https://tex.z-dn.net/?f=T_2%3D304.86%20K%3D304.86%20-273%5EoC%3D31.86%5EoC%5Capprox%2032.0%5EoC)
The new temperature of the water bath 32.0°C.
Answer:
The standard enthalpy of formation of this isomer of
is -220.1 kJ/mol.
Explanation:
The given chemical reaction is as follows.
![C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)](https://tex.z-dn.net/?f=C_%7B8%7DH_%7B18%7D%28g%29%2B%20%5Cfrac%7B25%7D%7B2%7DO_%7B2%7D%28g%29%20%5Crightarrow%208CO_%7B2%7D%28g%29%2B9H_%7B2%7DO%28g%29)
![\Delta H^{o}_{rxn}= -5104.1kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Brxn%7D%3D%20-5104.1kJ%2Fmol)
The expression for the entropy change for the reaction is as follows.
![\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Brxn%7D%3D%5B8%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28CO_%7B2%7D%29%20%2B9%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28H_%7B2%7DO%29%5D-%5B%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28C_%7B8%7DH_%7B18%7D%29%2B%20%5Cfrac%7B25%7D%7B2%7D%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28O_%7B2%7D%29%5D)
![\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28H_%7B2%7DO%29%3D%20-241.8kJ%2Fmol)
![\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28CO_%7B2%7D%29%3D%20-393.5kJ%2Fmol)
![\Delta H^{o}_{f}(O_{2})= 0kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28O_%7B2%7D%29%3D%200kJ%2Fmol)
Substitute the all values in the entropy change expression.
![-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]](https://tex.z-dn.net/?f=-5104.1kJ%2Fmol%3D%5B8%28-393.5%29%2B9%28-241.8%29kJ%2Fmol%5D-%5B%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28C_%7B8%7DH_%7B18%7D%29%2B%20%5Cfrac%7B25%7D%7B2%7D%280%29kJ%2Fmol%5D)
![-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})](https://tex.z-dn.net/?f=-5104.1kJ%2Fmol%3D-5324.2kJ%2Fmol%20-%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28C_%7B8%7DH_%7B18%7D%29)
![\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5E%7Bo%7D_%7Bf%7D%28C_%7B8%7DH_%7B18%7D%29%20%3D-5324.2kJ%2Fmol%20%2B5104.1kJ%2Fmol)
![=-220.1kJ/mol](https://tex.z-dn.net/?f=%3D-220.1kJ%2Fmol)
Therefore, The standard enthalpy of formation of this isomer of
is -220.1 kJ/mol.
Answer:
(B) HNO3 + NaOH
Explanation:
Hello,
In this case, for the production of sodium nitrate a substance having the sodium as a cation should react with another substance having the nitrate anion. Moreover, neutralization reactions are carried out when bases react with acids, such is the case of nitric acid and sodium hydroxide:
![NaOH+HNO_3\rightarrow NaNO_3+H_2O](https://tex.z-dn.net/?f=NaOH%2BHNO_3%5Crightarrow%20NaNO_3%2BH_2O)
Thus, the answer is (B) HNO3 + NaOH as the other options involve salts rather than acids or bases as starting reactants.
Regards.
One can expect to find the greatest amount of hydrolyzed pth when, entering the nephrons.
<h3><u>
Where would one expect to find the greatest amount of hydrolyzed pth ?</u></h3>
- In a healthy person, the body will respond by excreting calcium and PTH byproducts if plasma calcium is higher than usual. The nephron is a solid predictor since the kidneys are where excretion takes place.
- A) is false since PTH, not the hydrolyzed compounds, is produced by the parathyroid gland.
- One would anticipate significant amounts of PTH exiting the liver rather than entering since the liver hydrolyzes PTH.
- The largest concentration would still be in the nephrons, even if it is possible that some hydrolysis products will be in systemic circulation (and therefore penetrate the bones).
- The cortical bone, which is the outermost part of the bone, has a network of small tubes called haversian canals that let blood vessels and nerves to pass through them.
To view more about hydrolyzed pth, refer to:
brainly.com/question/4765096
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