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1 year ago

2. Are high trade deficits a worry?

Physics

1 answer:

Karo-lina-s [1.5K]1 year ago

5 0

Answer:

Trade deficit is always harmful to a country's economy

Explanation:

sorry i dont know how to explain

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A 50 wt% ni–50 wt% cu alloy is slowly cooled from 1400°c to 1200°c:

g100num [7]

This composition from Ni and Cu is called cupronickel.It is high in copper and silver in colour and highly resistant to corrosion, particularly seawater. Cooper nickel is used in the industry, in marine engineering . Melting point is 2254,73 F, which is 1234.85 Celsius. In this range of tempereature the cupronickel melts.

6 0

2 years ago

What is the magnitude of a the vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has

sladkih [1.3K]

The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 × $10^{6}$ N/C.

An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.

It is given that,

Mass of sphere, m = 2.1 g =0.0021kg

Charge,q = ₋3nC = ₋ 3 ₓ $10^{-9}$

To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,

$ma= qE$

a = g

$E = \frac{mg}{q}$

E = $\frac{0.0021 * 9.8}{-3 * 10^{-9} }$

E = 6860000 N/C

E = 6.86 × $10^{6}$ N/C

Hence, the magnitude of the electric field that balances its weight is 6.86 × $10^{6}$ N/C .

To know more about electric field refer to: brainly.com/question/8971780

#SPJ4

5 0

1 year ago

A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it wi

Free_Kalibri [48]

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

$K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A = \sqrt{\frac{1.25\ \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm$

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

6 0

2 years ago

If a truck loses 5610 J of energy as it slows down due to an external force of 425 N, what distance will it have moved after the

lara31 [8.8K]

Answer:

13.2m

Explanation:

Step one:

given data

Energy= 5610J

Force F= 425N

Required

The distance traveled

Step two:

We know that work done is given as

WD= force* distance

5610=425*d

divide both sides by 425

d= 5610/425

d=13.2m

3 0

3 years ago

What is the most likely outcome of increasing the number of slits per unit distance on a diffraction grating?1) lines become nar

Nina [5.8K]

It's important to know that diffraction gratings can be identified by the number of lines they have per centimeter. Often, more lines per centimeter is more useful because the images separation is greater when this happens. That is, the distance between lines increases.

<h2>Therefore, the answer is 2.</h2>

8 0

1 year ago