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kenny6666 [7]
4 years ago
6

You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 65o∘ with the horiz

ontal, and the hammer is moving at 9.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.
What is the horizontal component of the hammer's velocity just as it leaves the roof?
Express your answer with the appropriate units. Enter positive value if the x-component of the velocity is to the right and negative value if the x-component of the velocity is to the left.
What is the vertical component of the hammer's velocity just as it leaves the roof?
Express your answer with the appropriate units. Enter positive value if the direction of the y-component of the velocity is upward and negative value if the y-component of the velocity is downward.

Physics
1 answer:
Verizon [17]4 years ago
5 0

Answer:

v_x\approx4.0149\ m.s^{-1}

v_y\approx-8.6099\ m.s^{-1}

Explanation:

Given:

initial speed of the hammer when leaving the edge of the roof along the inclination of the roof, v=9.5\ m.s^{-1}

inclination of the roof form horizontal, \theta=65^{\circ}

  • Since the hammer is moving from the top of the roof to the right edge, its horizontal component will be towards right and vertical component will be towards downward direction.

Now the horizontal velocity:

v_x=v.\cos\theta

v_x=9.5\times \cos65^{\circ}

v_x\approx4.0149\ m.s^{-1}

<u>The vertical velocity:</u>

v_y=-v.\sin\theta

v_y=-9.5\times \sin65^{\circ}

v_y\approx-8.6099\ m.s^{-1}

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Explanation:

From the question, we have;

The frequency of the microwave beam emitted by the speed gun, f = 2.41 × 10¹⁰ Hz

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The Doppler shift for the microwave frequency emitted by the speed gun which is then reflected back to the gun by the moving baseball is given by 2 shifts as follows;

 \dfrac{\Delta f}{f} = \dfrac{2 \cdot v_{baseball}}{c}

\therefore{\Delta f}{} = \dfrac{2 \cdot v_{baseball}}{c} \times f

Where;

Δf = The change in frequency observed, known as the beat frequency = 3190 Hz

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By plugging in the values, we have;

\therefore{\Delta f} = 3190 \ Hz =  \dfrac{2 \cdot v_{baseball}}{3.0 \times 10^8 \ m/s} \times 2.41 \times 10^{10} \ Hz

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3 0
3 years ago
If the absolute temperature of a gas is 600 K, the temperature in degrees Celsius is: A. 705°C. B. 873°C. C. 273°C. D. 327°C
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m₂ = 0.200 kg

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u₁ = u₂ = 0 m/s

v₁ = ?

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In this system mechanical energy is conserved, so we can match its value in the horizontal position with the one in the vertical.

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