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3 years ago

What happens to the valence electrons of a metal and a nonmetal when they form an ionic bond

Physics

1 answer:

shusha [124]3 years ago

7 0

Answer:

Explanation:

Ionic bonds are also known as electrovalent bonds.

For ionic bonds to form, there is transfer of valence electrons from the metal to the non-metal. Metals are electropositive and would easily allow electrons to leave.

The goal of bonding is to achieve the octet configuration. An atom can lose or gain electrons to achieve this.

For example, to form NaCl, Na would loose its 1 valence electron. Cl would gain the Valence electron and complete it's octet with it.

This transfer of electron creates the ionic bond.

The metal which is less electronegative becomes positively charged. The non metal being more electronegative would become negatively charged.

Ionic compounds are polar compounds.

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Elaborate . on what can be learned about the properties by the location of element on the periodic table . Use atomic number 13

soldier1979 [14.2K]

Aluminum is a type of metal and that is a properties by the location of element

4 0

3 years ago

Read 2 more answers

A(n) 2602 kg van runs into the back of a(n)

forsale [732]

Answer:

8.5 m/s

Explanation:

please see paper for the work!

8 0

3 years ago

List two reasons for why a non-physicist might be interested in electrostatic interactions.

-Dominant- [34]

Answer:

all areas of knowledge that wish to understand the physical, chemical and biological process must know electrostatics

Explanation:

Electrostatic interactions, have many rare manifestations in nature, which causes many reasons to study them.

- Lightning is a very striking form of electricity

- The biological processes are governed by currents of inanes and potential differences

- The transfer of nutrients and fertilizers to plants is with ion exchange, electrostatic forces

- all modern electronics is based on electricity

- the electric charge in very dry places, creates high currents that can create fires or kill people

In summary all areas of knowledge that wish to understand the physical, chemical and biological process must know electrostatics

3 0

4 years ago

A thin, rectangular sheet of metal has mass M and sides of length a and b. Find the moment of inertia of this sheet about an axi

Lubov Fominskaja [6]

Answer:

The moment of inertia is $I=\frac{M}{12} a^{2}$

Explanation:

The moment of inertia is equal:

$I=\int\limits^a_b {r^{2} } \, dm$

If r is $-\frac{a}{2}$

and $dm=\frac{M}{a} dr$

$I=\int\limits^a_b {r^{2}\frac{M}{a} } \, dr\\a=\frac{a}{2} \\b=-\frac{a}{2}$

$I=\frac{M}{a} \int\limits^a_b {r^{2} } \, dr\\\\I=\frac{M}{a} (\frac{M}{3} )_{b}^{a}\\ I=\frac{M}{3a} (\frac{a^{3} }{8} +\frac{a^{3} }{8} )\\I=\frac{M}{12} a^{2}$

7 0

4 years ago

A 10-g bullet moving horizontally with a speed of 1.8 km/s strikes and passes through a 5.0-kg block initially at rest on a hori

UNO [17]

Answer:

6.4 J

Explanation:

m = mass of the bullet = 10 g = 0.010 kg

v = initial velocity of bullet before collision = 1.8 km/s = 1800 m/s

v' = final velocity of the bullet after collision = 1 km/s = 1000 m/s

M = mass of the block = 5 kg

V = initial velocity of block before collision = 0 m/s

V' = final velocity of the block after collision = ?

Using conservation of momentum

mv + MV = mv' + MV'

(0.010) (1800) + (5) (0) = (0.010) (1000) + (5) V'

V' = 1.6 m/s

Kinetic energy of the block after the collision is given as

KE = (0.5) M V'²

KE = (0.5) (5) (1.6)²

KE = 6.4 J

4 0

4 years ago