3 years ago

Method

Physics

1 answer:

dmitriy555 [2]3 years ago

6 0

Answer:

Explanation:

it's too because on you measuring mass of something

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Answer:

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b) $\dot m_{actual} = 1046.15 kg/s$

Explanation:

given data:

pressure ration rp = 12

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AT the end of isentropic process (compression) temperature is

$\frac{T_2'}{T_1} = rp ^{\frac{\gamma -1}{\gamma}}$

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$T_2' = 610.181 K$

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$\frac{T_3}{T_4'} = rp ^{\frac{\gamma -1}{\gamma}}$

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$w(compressor) = CP (T_2' -T_1)$

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b) actual mass flow rate uis given as

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$\dot m_{actual} = 1046.15 kg/s$

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