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Bezzdna [24]
3 years ago
7

What 281, 480,100 in word form

Mathematics
1 answer:
gregori [183]3 years ago
5 0
Two hundred eighty one million four hundred eighty thousand one hundred
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Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).
Elan Coil [88]

Answer:

(40/3)*pi

Step-by-step explanation:

lets first find the area of the little circle

A=pi*r^2

A=pi*3^2

A=9pi

Now, lets find the area of the big circle

A=pi*r^2

A=pi*(3+4)^2

A=pi*7^2

A=49pi

now lets subtract the area of the little circle from the area of the big circle

49pi-9pi=40pi, now we found the area of the "bagel)

lets find what portion of the bagel is the shaded region

120/360=1/3

now lets multiply the bagel area by the fraction

40pi*(1/3)=

(40/3)*pi   or  (40*pi)/3

4 0
3 years ago
80% more then $20.00
ElenaW [278]

Answer

$36

Step-by-step explanation:

You multiply 0.8 by 20 since 0.8 is also 80% and you get 16. Since you want 80% more than 20 you add together to get $36. Hope it helped!

6 0
3 years ago
Read 2 more answers
Select the tables that show a proportional relationship between x and
forsale [732]

Answer:

213`334

Step-by-step explanation:

sry lol i want points i apologize

4 0
2 years ago
You lean a 30 foot ladder against your house and it reaches exactly to the top. The ladder makes a 24 degree angle with the grou
zhenek [66]
A right triangle is formed with the ladder as the hypotenuse. Since the angle made by the ladder with with ground is given, we can use trigonometric functions to solve for the height of the house.

If we let x be the height of the house and using sine function:
sin 24 = x/30
x = 30 sin 24
x = 12.20 ft

Therefore, the house is 12.20 ft tall
4 0
2 years ago
Q. A room measure 3m 55cm by 2m 25 cm. What is the perimeter of the room?
Bond [772]

Answer:

100cm = 1m

Thus, one more step should be added to your working to arrive at the final answer:

Perimeter

= 10m 160cm

= 11m 60cm

This is because 160cm= 100cm +60cm, which is also equivalent to 1m 60cm.

Alternative working:

Convert all the units to cm first.

\boxed{1 \: m= 100 \: cm}

Length

= 5m 55cm

= 300cm +55cm

= 355cm

Breadth

= 2m 25cm

= 200cm +25cm

= 225cm

Perimeter

= 2(length +breadth)

= 2(355 cm +225 cm)

= 2(580 cm)

= 1160 cm

= 11m 60cm

From the second last step to the last step, you could divide 1160 by 100 to find how many meters are there. You would get a quotient of 11 and a remainder of 60. Since this 60 cannot be changed into meters as a whole number, we can leave it as 11m 60cm. Otherwise, it is also correct to leave it as 1160cm or 11.6m unless otherwise stated.

However, 10m 160cm is not preferred since the conversion of cm to m is done partially, as the 160 cm can still be further simplified.

8 0
2 years ago
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