Answer:
Students A, B, and E
Explanation:
Student A is playing in the lab, student B is sniffing the flask, you're supposed to waft, and student E is eating while working.
Then you will multiply the number of moles by 6.022×1023formula units/mol . To determine the molar mass of a compound, add the atomic weight on the periodic table in g/mol times each element's subscript. Since the formula unit CaO has no subscripts, they are understood to be 1
Answer: Andre. If it is used as an antifreeze, one would infer that it's freezing point is less than water.
Explanation:
The freezing point of ethylene glycol alone (100%) is -12.9oC. That is somewhat less than the freezing point of water but nowhere near the freezing point of water containing 70% ethylene glycol.
Hello!!!
what exactly are you wanting to know? It isn’t clear from your question. Please advise and I will answer it for you ASAP. I think I know what you are wanting but I don’t want to assume.... thank you
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Answer:</h3>
51.93 L
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Explanation:</h3>
From the question we are given the following components of an ideal gas;
Number of moles = 21.5 mol
Pressure, P = 9.65 atm
Temperature, T = 10.90°C, but K= °C + 273.15
=284.05 k
We are required to calculate the volume of the ideal gas.
We are going to use the ideal gas equation which is given by;
PV = nRT, where P, V, T and n are the pressure, volume, temperature and moles of the ideal gas respectively. R is the ideal gas constant, 0.082057 L.atm/mol.K
To get the volume, we rearrange the formula to get;
V = nRT ÷ P
= (21.5 × 0.082057 × 284.05 K) ÷ 9.65 atm
= 51.93 L
Thus, the volume of the ideal gas is 51.93 L
