Answer: The answer is B) 1.00 M CaCl2
Explanation: I just did it on usatestprep and it said it was correct .
Answer:
Moles of BCl₃ needed = 0.089 mol
Explanation:
Given data:
Moles of BCl₃ needed = ?
Mass of HCl produced = 10.0 g
Solution:
Chemical equation:
BCl₃ + 3H₂O → 3HCl + B(OH)₃
Number of moles of HCl:
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 36.46 g/mol
Number of moles = 0.27 mol
Now we will compare the moles of HCl with BCl₃.
HCl : BCl₃
3 : 1
0.27 : 1/3×0.27 = 0.089 mol
2 C3H6 + 2 NH3 + 3 O2 -> 2 C3H3N + 6 H2O
Molar masses
C3H6: 42.08 g/mol
NH3: 17.03 g/mol
O2: 32 g/mol
CH3H3N: 53.06 g/mol
H2O: 18 g/mol
# of moles
C3H6: 15.0 g / [42.08 g/mol] = 0.356 mol
NH3: 5.00 g / [17.03 g/mol] = 0.294 mol
O2: 10.0 g / [32 g/mol] = 0.313 mol
Now wee need to find the limitant reactant
The theoretical proportion is 2:2:3, equivalent to 1:1:1.5
The proportion ot the given gases is 0.356 : 0.294 : 0.313, dividing by 0.294 that is equivalent to: 1.2 : 1 : 1.06, where you see that O2 is below the theoretical proportion and it is the limitant reactant.
Now, from the equation you have 3 mol of O2 produces 2 mol of acrylonitrile (C3H3N)
Then you will obtain 0.313 * 2/3 = 0.209 mol acrylonitrile
The mass is 0.209mol * 53.06 g/mol = 11.07 g acrylonitrile
Answer: 11.07 g
Answer:
Maybe is D....
Explanation:
When the hydrogen peroxide decomposed,it graph such as A so maybe the formation of hydrogen peroxide is opposite direction as the A....Hope can help you.....