Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
Explanation:
Conjugated diene is the one that contains alternate double bonds in its structure. That means both the double bonds are separated by a single bond.
Cumulated diene is the one that contains two double bonds on a single atom. This means it has two double bonds continuously.
Isolated double-bonded compound has a single bond isolated by two to three single bonds.
Compound A: Two alkenes are joined by a sigma bond.
For example:
It is a conjugated diene.
Compound B: Two alkenes are joined by a C H 2 group.
It is a cumulative diene.
Compound C: Two alkenes are joined by C H 2 C H 2.
Then it is an isolated alkene.
Compound D: A cyclohexene has a double bond between carbons 1 and 2. Carbon 3 is an sp 2 carbon that is bonded to another s p 2 carbon with an alkyl substituent.
Hence, compound D is a conjugated diene.
Answer:
Explanation:
To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.
The equation is:
PiTo = PoTi
Where:
<em>Pi =initial pressure</em>
<em>Po = final pressure</em>
<em>Ti = initial temperature</em>
<em>To = final temperature</em>
Let's use this equation and replace the values:
<em>Pi = 107 kPa</em>
<em>Ti = 22°C</em>
<em>To = 45 °C </em>
<em>Po = ? </em>
<em />
You can use the units as the problem gave you.
Using the Gay Lussac law:
107 kPa x 45 °C = Po x 22°C
Po = (4,815 kPa°C / 22°C) = 218.86 kPa
Po = 218 kPa
Balance Chemical Equation of this reaction is,
2 CO + O₂ → 2CO₂
Acc. to this reaction,
88 g (2 mole) of CO₂ was produced when = 56 g (2 mole)of CO was reacted
So,
24.7 g of CO₂ will be produced by reacting = X g of CO
Solving for X,
X = (56 g × 24.7 g) ÷ 88 g
X = 2.26 g ÷ 88 g
X = 0.0257 g of CO
Result:
0.0257 g of CO is required to be reacted with excess of O₂ to produce 24.7 g of CO₂.