Answer:
The correct option is B. an alpha particle.
Explanation:
When ²³Na is bombarded with protons
, ²⁰Ne and one alpha particle
is released.
The reaction is as follows:

Therefore, an alpha particle and ²⁰Ne are released when ²³Na is bombarded with protons.
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Answer:
I think the answer is C. for 4. and then B. for 5.
Answer:

Explanation:
Given:
- mass of bullet,
- initial velocity of bullet,

- displacement of the bullet in the target,

Here as given in the question the bullet penetrates the target by the given displacement of the bullet into it. During this process it faces deceleration and hence it comes to rest.
- so, final velocity of the bullet,

Now using the equation of motion:

where:
acceleration of the bullet


<u>Now the force of resistance offered by the target in stopping it:</u>



Answer:
V = E * d
E = (200 J/C) / .024 m = 8330 J / C-m
1/2 m v^2 = V q potential energy of electron
v^2 = 2 * 200 J/C * 1.6E-19 C / 9.11 E-31 kg
v^2 = 400 * 1.6E-19 / 9.11 E-31 N-m / kg
v = 8.4E6 m/s