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xxTIMURxx [149]
3 years ago
7

Whta would you call this?

Physics
2 answers:
Thepotemich [5.8K]3 years ago
8 0
A model of what Shoulder pain looks like...
NeTakaya3 years ago
7 0
Hello,

I would call this a figurine maybe rubbing his shoulder due to stress, or a figurine standing for the Pledge of Allegiance (United States).

Faith xoxo
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When 23Na is bombarded with protons, the products are 20Ne and A. a neutron B. an alpha particle C. a deuteron D. a gamma ray pa
Vikki [24]

Answer:

The correct option is B. an alpha particle.

Explanation:

When ²³Na is bombarded with protons _{1}^{1}\textrm{H}, ²⁰Ne and one alpha particle _{2}^{4}\textrm{He} is released.

The reaction is as follows:

_{11}^{23}\textrm{Na} + _{1}^{1}\textrm{H} \rightarrow _{10}^{20}\textrm{Ne} + _{2}^{4}\textrm{He}

Therefore, an alpha particle and ²⁰Ne are released when ²³Na is bombarded with protons.

5 0
4 years ago
What is the ultimate source of energy for all living things
miskamm [114]
The sun . plz give me a nice thank you 
3 0
3 years ago
WILL MARK BRAINLIST!!! only for correct answer
adelina 88 [10]

Answer:

I think the answer is C. for 4. and then B. for 5.

4 0
3 years ago
A 15.0 g bullet is moving to the right with speed 270 m/s when it hits a target and travels an additional 25.0 cm into the targe
Fantom [35]

Answer:

F=2187\ N

Explanation:

Given:

  • mass of bullet,m=15\ g=0.015\ kg
  • initial velocity of bullet, u=270\ m.s^{-1}
  • displacement of the bullet in the target, s=25\ cm=0.25\ m

Here as given in the question the bullet penetrates the target by the given displacement of the bullet into it. During this process it faces deceleration and hence it comes to rest.

  • so, final velocity of the bullet, v=0\ m.s^{-1}

Now using the equation of motion:

v^2=u^2+2a.s

where:

a= acceleration of the bullet

0^2=270^2+2a\times 0.25

a=145800\ m.s^{-2}

<u>Now the force of resistance offered by the target in stopping it:</u>

F=m.a

F=0.015\times145800

F=2187\ N

5 0
3 years ago
What is the magnitude of electric field between 2 charged plates that are separated by a distance of 2.4cm, if the voltage acros
Radda [10]

Answer:

V = E * d    

E = (200 J/C) / .024 m =   8330 J / C-m  

1/2 m v^2 = V q      potential energy of electron

v^2 = 2 * 200 J/C * 1.6E-19 C / 9.11 E-31 kg

v^2 = 400 * 1.6E-19 / 9.11 E-31   N-m  / kg

v = 8.4E6 m/s

7 0
2 years ago
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