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Monica [59]
1 year ago
8

Please help me with this

Chemistry
1 answer:
Sophie [7]1 year ago
7 0

Answer:

5.0 38 84.0 749.7 528.0 729.0 738.9 739.0

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You wish to make a 0.405 M hydrochloric acid solution from a stock solution of 3.00 M hydrochloric acid. How much concentrated a
Vesnalui [34]

Answer:

Explanation:

We have to make 100 mL 0f .405M HCl from 3 M solution of HCl .

volume of 3M to be taken required . Let this volume be V litre .

V litre of 3M will contain 3 V moles of HCl .

moles contained by 100 mL of ,405 HCl = .405 x .1 = .0405 moles .

So 3V = .0405

V = .0405 / 3 litre

= .0405 x 1000 / 4 mL

= 10.125 mL

So we have to take 10.125 mL of 3M HCl and add water to them to make its volume 100 mL .

4 0
3 years ago
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
fomenos

Answer:

The total pressure after one half is 6.375 atm.

Explanation:

The initial pressure of product is increases while the pressure of reactant would decrease.

Balanced chemical equation:

2N₂O  → 2N₂ + O₂

The pressure of N₂O is 5.10 atm. The change in pressure would be,

N₂O = -2x

N₂ = +2x

O₂ = +x

The total pressure will be

P(total) = P(N₂O) + P(N₂)  + P(O₂)

P(total) = ( 5.10 - 2x) + (2x)  + (x)

P(total) = 5.10 + x

After one half life:

P(N₂O)  = 1/2(5.10) = 5.10 - 2x

x = 5.10 - 1/2(5.10) /2

x = 5.10 - 0.5 (5.10) /2

x = 5.10 - 2.55 / 2

x = 2.55 /2 = 1.275 atm

Thus the total pressure will be,

P(total) = 5.10 + x

P(total) = 5.10 + 1.275

P(total) = 6.375 atm

4 0
3 years ago
Consider the reactionI2(g) + Cl2(g)2ICl(g)Using standard thermodynamic data at 298K, calculate the entropy change for the surrou
Georgia [21]

We know,

\Delta H_{I_2(g)}=62.438\ KJ/mol\\\\\Delta H_{Cl_2(g)}= 0.0\ KJ/mol\\\\\Delta H_{ICl(g)}=17.78\ KJ/mol

For given reaction, I_2(g)+Cl_2(g)\ -->\ 2ICl(g)

\Delta H_{rxn}=2\Delta H_{ICl(g)}-\Delta H_{I_2(g)}-\Delta H_{Cl_2(g)}\\\\\Delta H_{rxn}=2(17.78)-0-62.438\ KJ/mol\\\\\Delta H_{rxn}=-26.878\ KJ/mol

For , 2.41 moles of I_2 :

\Delta H_{rxn}=2.41\times (-26.878)\ KJ\\\\\Delta H_{rxn}=-64.78\ KJ

We know :

\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K

Hence, this is the required solution.

7 0
3 years ago
Propose a plausible mechanism for the following transformation: For the mechanism, draw the curved arrows as needed. Include lon
monitta

Answer:

The question is incomplete. The mechanism is not included in your question. The attached file contains the mechanism and the proposed mechanism.

Explanation:

See the attached file for the structure.

5 0
3 years ago
The chemical name for the compound formula NaCl is?
Mandarinka [93]

Answer:

The chemical name for the compound formula NaCl is sodium chloride.

7 0
3 years ago
Read 2 more answers
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