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m_a_m_a [10]
3 years ago
6

A chemist have to fill a 500 mL beaker with saturated solution of sodium nitrate and water at room temperature. How could the ch

emist increase the concentration of sodium nitrate in the solution
A) pour out some of the solution from the beaker, then add pure water
B) add more sodium nitrate to the beaker and raise the temperature
C) pour out some of the solution from the beaker
D) add more sodium nitrate to the beaker and decrease the temperature
Chemistry
2 answers:
geniusboy [140]3 years ago
7 0

Answer:

pour out some of the solution from the beaker

Oksi-84 [34.3K]3 years ago
3 0

Answer:

c

Explanation:

gradpoint

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Answer:

12 grams

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an atmosphere is considered hazardous if it contains a hazardous gas in excess of 10 percent of the hazardous material's:
svlad2 [7]

Lower flammable limit means the lowest concentration of a material that will propagate a flame.

What is hazardous atmosphere?

It is an atmosphere that may expose employees to risk of death, incapacitation, impairment of ability to self-rescue, injury, or acute illness from one or more of following causes

  • Flammable gas, vapor, or mist in excess of 10 percent of lower flammable limit (LFL)
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What is lower flammable limit?

  • It means the lowest concentration of a material that will propagate a flame.
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  • Atmospheres with concentration of flammable vapors at or above 10 percent of lower explosive limit (LEL) are considered hazardous when located in confined spaces.
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1 year ago
If another student joins the game and stands behind the two students
Mandarinka [93]

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4 0
2 years ago
Who discovered the electron and what instrument did he use?
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8 0
3 years ago
Calculate the molar solubility of CaF2 at 25°C in a solution that is 0.010 M in Ca(NO3)2. The Ksp for CaF2 is 3.9 x 10-11.
madreJ [45]

Answer:

Molar \ solubility=3.12x10^{-5}M

Explanation:

Hello,

In this case, for the dissociation of calcium fluoride:

CaF_2(s)\rightleftharpoons Ca^{2+}+2F^-

The equilibrium expression is:

Ksp=[Ca^{2+}][F^-]^2

In such a way, via the ICE procedure, including an initial concentration of calcium of 0.01 M (due to the calcium nitrate solution), the reaction extent x is computed as follows:

3.9x10^{-11}=(0.01+x)(2*x)^2\\\\x=0.0000312M

Thus, the molar solubility equals the reaction extent x, therefore:

Molar \ solubility=3.12x10^{-5}M

Regards.

4 0
3 years ago
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