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2 years ago

Nylones are: a, amides b, polymides

Chemistry

1 answer:

wlad13 [49]2 years ago

6 0

Nylon is a polymide.

Hope it helps you

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What is the [h3o+] for a solution at 25°c that has poh = 5.640?

jonny [76]

Answer:

= 4.37*10^-9 M

Explanation:

We know that;

pH + pOH = 14

Therefore;

pH = 14 - pOH

Which means; pH = 14 - 5.64

= 8.36

But;

pH = -log[H3O+]

Thus;

8.36 = -log[H3O+]

[H3O+] = 10^(-8.36)

= 4.37*10^-9 M

5 0

3 years ago

Use the periodic table to identify the element indicated by each electron configuration by typing in the

EleoNora [17]

Answer:

1s22s22p6: Neon (Ne)

1s22s22p63s23p3: Phosphorous (P)

1s22s22p63s23p64s1: Potassium (K)

1s22s22p63s23p64s2(im not sure what 308 is supposed to be): Calcium (Ca)

1s22s22p63s23p64s23d104p65s24d3: there is no pure element that ends 4d3 that I know of so this can either be Zirconium(Zr) if it ends in 4d2 or Niobium (Nb) if it ends in 4d4

Explanation:

you can look at the periodic table and the trends to find the rough idea of where the electron configuration ends, there are helpful articles and images on these, i attached an image that may help. After that you can look at the atomic number to find the number of electrons for a pure element and use the electron subshell pattern thing to find the exact number

5 0

1 year ago

Water vapor condenses into a glass of water. The water is then placed in a freezer and changes into ice. What remains consistent

PolarNik [594]

Chemical properties

8 0

3 years ago

3. A helium laser emits light with a wavelength of 6.33 x 10^-7m. What is

HACTEHA [7]

Answer:

4.52 x 10¹⁴ cycles/s

Explanation:

From c = f·λ => f = c/λ = (3.0 x 10⁸ m/s)/(6.63 x 10⁻⁷m) = 4.52 x 10¹⁴ cycles/s.

f = frequency = ?

λ = wavelength = 6.63 x 10⁻⁷ meter

c = speed of light in vacuum = 3.0 x 10⁸ meters/s

7 0

2 years ago

The reactant concentration in a second-order reaction was 0.560 m after 115 s and 3.30×10−2 m after 735 s . what is the rate con

Aloiza [94]

Use the formula for second order reaction:

$\frac{1}{C} = \frac{1}{C_0} + kt$

C = concentration at time t
C0 = initial conc.
k = rate constant
t = time

1st equation : $\frac{1}{0.56} = \frac{1}{C_0} + 115k$

2nd Equation: $\frac{1}{0.033} = \frac{1}{C_0} + 735k$

Find $\frac{1}{C_0}$ from 1st equation and put it in 2nd equation:

$\frac{1}{0.033} = \frac{1}{0.56} - 115k + 735k$

$\frac{1}{0.033} - \frac{1}{0.56} = 620k$

k = 0.046

3 0

3 years ago