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3 years ago

Why doesn't the evaporation flask have bubbles below the surface

1 answer:

7 0

It doesnt have bubbles below the surface because as the heat is rising while it is evapoarting the heat is going upward towards the surface or object

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What do you notice about the relationship between the force strength and the size of the velocity change?

ella [17]

Answer:

a mass is constant during -free-weight training,a greater impulse will result in greater velocity.therefore as a generation of force greater than weight of the resistance increases.

4 0

3 years ago

How many liters of hydrogen gas will be produced at STP from the reaction of 7.179×10^23 atoms of magnesium with 54.219g of phos

Alexeev081 [22]

Answer: The volume of hydrogen gas produced will be, 12.4 L

Explanation : Given,

Mass of $H_3PO_4$ = 54.219 g

Number of atoms of $Mg$ = $7.179\times 10^{23}$

Molar mass of $H_3PO_4$ = 98 g/mol

First we have to calculate the moles of $H_3PO_4$ and $Mg$ .

$\text{Moles of }H_3PO_4=\frac{\text{Given mass }H_3PO_4}{\text{Molar mass }H_3PO_4}$

$\text{Moles of }H_3PO_4=\frac{54.219g}{98g/mol}=0.553mol$

and,

$\text{Moles of }Mg=\frac{7.179\times 10^{23}}{6.022\times 10^{23}}=1.19mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$3Mg+2H_3PO_4\rightarrow Mg(PO_4)_2+3H_2$

From the balanced reaction we conclude that

As, 3 mole of $Mg$ react with 2 mole of $H_3PO_4$

So, 0.553 moles of $Mg$ react with $\frac{2}{3}\times 0.553=0.369$ moles of $H_3PO_4$

From this we conclude that, $H_3PO_4$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $H_2$

From the reaction, we conclude that

As, 3 mole of $Mg$ react to give 3 mole of $H_2$

So, 0.553 mole of $Mg$ react to give 0.553 mole of $H_2$

Now we have to calculate the volume of $H_2$ gas at STP.

As we know that, 1 mole of substance occupies 22.4 L volume of gas.

As, 1 mole of hydrogen gas occupies 22.4 L volume of hydrogen gas

So, 0.553 mole of hydrogen gas occupies $0.553\times 22.4=12.4L$ volume of hydrogen gas

Therefore, the volume of hydrogen gas produced will be, 12.4 L

4 0

3 years ago

At equilibrium A. All reactions have ceased B. Only the forward reaction continues C. Only the reverse reaction continues D. Bot

vovangra [49]

Answer:

D)both the forward and reverse reactions continue.

Explanation:

Chemical equilibrium can be regarded as state whereby rate of the forward reaction is equal to rate of backward reaction. It should be noted that At equilibrium both the forward and reverse reactions continue.

8 0

3 years ago

M is a mysterious element whose molar mass is 141.0 g/mol. When combined with oxygen, the formula of the compound is M2O5. What

Alex Ar [27]

Answer:

I d k

Explanation:

7 0

3 years ago

An element Y has 13 protons . with reference on Y answer these questions •

kobusy [5.1K]

Explanation:

Y has 13 protons and we know that Aluminium (Al) too has 13 protons.

So , element Y = Aluminium

• In an element , no. of protons = no. of electrons. So , Y has 13 electrons.

• Mass no. of Y (Aluminium) = 27.

• Also we know that ,

Mass number = no. of protons + no. of neutrons

So,

No. of neutrons = 27 - 13 = 14

• Valence electrons are the electrons which are present in the outermost shell of an element.

Electronic Configuration of Y = 2,8,3

So, Y has 3 valence electrons.

• We know that Y is Aluminium & Aluminium is a metal. So , Y is a metal.

• Valency of Y = +3

7 0

3 years ago