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3 years ago

What is the boiling point (in °C) of a 0.743 m aqueous solution of KCI?

Chemistry

1 answer:

pishuonlain [190]3 years ago

6 0

The correct answer is 100.761

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The envelope of air that surrounds the earth is called

svlad2 [7]

Atmosphere is the envelope of air that surrounds the earth.

4 0

3 years ago

(Atomic masses used are C = 12.0 g mol–1, O = 16.0 g mol–1, H = 1.01 g mol–1, Cu = 63.5 g mol–1,)

alex41 [277]

Question 1

The formula mass of methanol is $12.0+3(1.01)+16.0+1.01=32.04$ g/mol.

Therefore, in 5.0 grams of methanol, there are $5.0/32.04=\boxed{0.16}$ moles.

Question 2

The formula mass of copper(II) carbonate is $63.5+12.0+3(16.0)=123.5$ g/mol.

This means that in 9.0 grams of copper(II) carbonate, there are $9.0/123.5=0.072874493927126$ moles.

Using Avogradro's number, there are $(0.072874493927126)(6.022 \times 10^{23})=\boxed{4.4 \times 10^{22}}$ molecules.

Question 3

The formula mass of cyclohexane is $12.0(6)+1.01(12)=84.12$ g/mol.

So, 3.0 grams of cyclohexane is the same as $3.0/84.12=\boxed{0.036}$ moles.

Question 4

The formula mass of benzene is $12.0(6)+1.01(6)=78.06$ g/mol.

This means that 4.00 moles of benzene has a mass of $(78.06)(4.00)=\boxed{312}$ grams.

Question 5

1000 atoms of calcium is the same as $\frac{1.000}{6.022 \times 10^{23}}$ moles.

This is equal to $\frac{1000}{6.022 \times 10^{23}} \cdot 40.078=\boxed{6.7 \times 10^{-20}}$ grams.

6 0

1 year ago

D is a green crystalline solid that dissolves in water to give a very pale green solution addition of sodium hydroxide solution

Ksivusya [100]

Answer:

I think its iron(II) oxide

Explanation:

The substance is black but when it's mixed with water it turns green solution so when mixed with sodium Hydroxide it turns green

5 0

3 years ago

the Temperature of a sample of an ideal gas in a sealed 5.0 l container is raised from 27 oC to 77oC. If the initial pressure of

matrenka [14]

Answer:
The pressure increases to 3.5 atm.

Solution:
According to Gay-Lussac's Law, " At constant volume and mass the pressure of gas is directly proportional to the applied temperature".

For initial and final states of a gas the equation is,

P₁ / T₁ = P₂ / T₂
Solving for P₂,
P₂ = P₁ T₂ / T₁ ----- (1)

Data Given;
P₁ = 3 atm

T₁ = 27 °C + 273 = 300 K

T₂ = 77 °C + 273 = 350 K

Putting values in eq. 1,

P₂ = (3 atm × 350 K) ÷ 300 K

P₂ = 3.5 atm

7 0

3 years ago

In a nuclear reaction, the energy released is equal to 8.1 x 1016 joules. Calculate the mass lost in this reaction. (1 J = 1 kg

makvit [3.9K]

Use the formula E=mc^2
energy given=8.1 x 10^16 joules
speed of light = 3.00 × 10^8 m/s

plug in the values we'll get mass=9.0 x 10-1 kg

5 0

3 years ago

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