Answer:
In the figure below, m<4=50. Find ,m<1 , m<2 and m<3.In the figure below, m<4=50. Find ,m<1 , m<2 and m<3.In the figure below, m<4=50. Find ,m<1 , m<2 and m<3.In the figure below, m<4=50. Find ,m<1 , m<2 and m<3.
Step-by-step explanation:
a
Answer:
375 adult tickets were sold
Step-by-step explanation:
We know that the total amount of tickets sold is 805 tickets so that is our sum.
Then we know that there were 55 more student tickets sold than adult tickets. Since we don't know the amount of student tickets, we will use x.
So you would use x+55 for the student tickets.
Now, we don't know how many adult tickets either so we will use x for the amount of adult tickets.
So now, our equation would be:
805= x+55+x
Simplify:
805= 2x+55
Subtract 55 from both sides:
750= 2x
Divide each side by 2 so that we get x by itself:
375=x
Since x equals 375, there were 375 adult tickets sold.
Scientific notion always has a number times 10 to the power of something.
So
Now if you had to round then it would become
<span>We add the products of the chance a bridge collapses while the other two bridges do not collapse.
P(Only Elder collapses) = .14*.96*.8 = 0.10752
P(Only Younger collapses) = .86*.04*.8 = 0.02752
P(Only Ancient collapses) = .86*.96*.2 = 0.16512
P(Only one bridge collapses) = 0.10752 + 0.02752 + 0.16512 = 0.30016
Round the probability to four decimal places giving the solution of 0.3002 as the probabilityof exactly one bridge collapse in the next year.</span>
