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1 year ago

How did I get this wrong?

Mathematics

2 answers:

Nastasia [14]1 year ago

8 0

-2 and -1 are all more than -3. (not sure if 0 would need to be marked)

goblinko [34]1 year ago

7 0

Answer:

you didnt add an actual line

Step-by-step explanation:

you have to add a ray, which counts as a line in this case, which goes from 1 to 5 and beyond. (the arrow should point right from the 5)

the second ray has to start from -4 and the arrow has to be left from -5.

you have to add the rays because the question is asking for a number line

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2 years ago

Round to the nearest hundred thousand 257,098

olga nikolaevna [1]

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2 years ago

Find the interquartile range and range of 125,17,23,16,21,18,16,15,11,35,18,24,18,3

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2 years ago

Read 2 more answers

Integration: How would I get to this answer?

Scrat [10]

Given that $y$ attains a maximum at $x=1$ , it follows that $y'=0$ at that same point. So integrating once gives

$\displaystyle\int\frac{\mathrm d^2y}{\mathrm dx^2}\,\mathrm dx=\int-8x\,\mathrm dx$
$\dfrac{\mathrm dy}{\mathrm dx}=-4x^2+C_1$
$\implies -4(1)^2+C_1=0\implies C_1=4$

and so the first derivative is $y'=-4x^2+4$ .

Integrating again, you get

$\displaystyle\int\frac{\mathrm dy}{\mathrm dx}\,\mathrm dx=\int(-4x^2+4)\,\mathrm dx$
$y=-\dfrac43x^3+4x+C_2$

You know that this curve passes through the point (2, -1), which means when $x=2$ , you have $y=-1$ :

$-1=-\dfrac43(2)^3+4(2)+C_2$
$\implies C_2=\dfrac53$

and so

$y=-\dfrac43x^3+4x+\dfrac53$

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3 years ago

La diferencia es la respuesta a un problema de....

velikii [3]

Answer:

sorry to say this but if you write the question in english it would be easy to understand

Step-by-step explanation:

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3 years ago