<span>number Moles of C = 54.5 g / 12.011 = 4.54
number Moles of H = 9.10 / 1.008 = 9.02
number Moles of O = 36.4 / 16 = 2.28
if we want to divide by the smallest number
4.54 / 2.28 = 2 => C
9.02 / 2.28 = 4 => H
2.28 / 2.28 = 1 => O
Empirical formula will be = C2H4O</span>
We know that density = mass /volume
so
mass=volume*density
volume=mass/density
so c is wrong
Balance the chemical equation for the chemical reaction.
Convert the given information into moles.
Use stoichiometry for each individual reactant to find the mass of product produced.
The reactant that produces a lesser amount of product is the limiting reagent.
The reactant that produces a larger amount of product is the excess reagent.
To find the amount of remaining excess reactant, subtract the mass of excess reagent consumed from the total mass of excess reagent given.
<span>Tf is the freezing point of the solution(the solvent plus solute).
T*f is the freezing point of the pure solvent(without solute)
i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1.
Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol.
Tf is -1.58 Degree C</span>
