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masya89 [10]
3 years ago
15

The decomposition of SOCl2 is first-order in SOCl2. If the half-life for the reaction is 4.1 hr, how long would it take for the

concentration of SOCl2 to drop from 0.36 M to 0.045 M?
Chemistry
1 answer:
qaws [65]3 years ago
3 0
4.1 h = 14760 s 

<span>t 1/2 = ln 2 / k </span>

<span>k = rate reaction = 4.97 x 10^-5 </span>

<span>ln 0.045 / 0.36 = - 4.97 x 10^-5 t </span>

<span>2.08 = 4.97 x 10^-5 t </span>

<span>t = 41839.9 s = 11 h 37 min 19 s</span>
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