Answer:
See below ~
Step-by-step explanation:
<u>Drawing the rectangle</u> (Refer attachment)
<u>Horizontal sides</u>
- There are two x-values present : 1 and 6
- Find the difference
- 6 - 1 = 5
- The horizontal sides of the rectangle are <u>5</u> units long
<u>Vertical sides</u>
- Two y-values are present : 4 and 5
- Find the difference
- 5 - 4 = 1
- The vertical sides of the rectangle are <u>1</u> unit long
<u>Perimeter</u>
- 2(Horizontal side + Vertical side)
- 2(5 + 1)
- 2(6)
- 12
- The perimeter of the rectangle is <u>12</u> units
The value of x is about 4.7
Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
Step-by-step explanation:
We can rewrite left side into right side form
(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
we can expand it
(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4
(x^2+y^2)^2=x^4+y^4+2x^2y^2
we can add and subtract 2x^2y^2
(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2
(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2