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lesya692 [45]
3 years ago
10

800+900×25-65(89+5)-12÷67-7​

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

As there is Bracket lats solve it first but as there is '-' sign before the bracket sign in the bracket will change. so we will have,

'800+900×25-65(89-5)-12÷67-7'

Solving the bracket gives us:

'800+900×25-65(84)-12÷67-7'

Now avoiding the Bracket:

'800+900×25-5460-12÷67-7'

Now first we have to do MUltiplication, so we will get,

'800+22500-5460-12÷67-7'

Now let's do the division, so we will get,

'800+22500-5460-0.17-7'

Now lets do the additions and subtractions we will get,

<h2><u>17,832.83</u></h2>
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Igoryamba

Answer:

D. \sqrt{250}

Step-by-step explanation:

First, use prime factorization of 250 to get \sqrt{2*5^3}

Then apply the exponent rule, a^{b+c} =a^{b}*a^{c}

=\sqrt{2*5^2*5} }

Apply radical rule: \sqrt{ab}= \sqrt{a}  \sqrt{b}, a\geq 0, b\geq 0

=\sqrt{5^{2}}  \sqrt{2*5}

Apply radical rule: \sqrt{a^{2}} =a, a\geq 0

=5\sqrt{2*5}

=5\sqrt{10}

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3 years ago
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Solve the following system of equations by elimination. What is the value of y?
lbvjy [14]

Answer:

y = 3

Step-by-step explanation:

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-3x + 2y = -18 ---------------(ii)

(i) * 3               6x - 15y = 3

(ii)*2             <u> -6x + 4y = -36</u>

add==>                  -11y = -33

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5 0
3 years ago
The estimated number of organisms in a population after t days is shown in the table below. t days estimated number of organisms
Lelu [443]

Answer:

The function n=591.68(1.2056)^t best models the situation.

Step-by-step explanation:

The values in the table do not lie over a straight line because their slope is not a constant; for example

m_1=\frac{1250=860}{4-2} =195

m_2=\frac{1850-1250}{2}=275

we see here that m_1\neq m_2 therefore a linear equation cannot represent this situation.

The values in the table are increasing exponentially , therefore the equation modeling the situation will be of the form:

n=ab^t

we take two points from the table for evaluating a and b namely points (2,860) and (4,1250)

thus we have

(1). 860=ab^2

(2).1250=ab^4

From equation (1) we solve for a:

a=\frac{860}{b^2}

and put this value into equation (2)

1250 =\frac{860}{b^2}b^4

b^2=\frac{1250}{860}

\boxed{b=1.2056}

with this value b , we solve for a in equation (1):

860=a(1.2056)^2

a=\frac{860}{(1.2056)^2}

\boxed{a=591.68}

Thus we have the equation

\boxed{n=591.68(1.2056)^t}

8 0
3 years ago
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If you divide both sides by -4 you'll get:

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