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lesya692 [45]
2 years ago
10

800+900×25-65(89+5)-12÷67-7​

Mathematics
1 answer:
vlada-n [284]2 years ago
4 0

Answer:

As there is Bracket lats solve it first but as there is '-' sign before the bracket sign in the bracket will change. so we will have,

'800+900×25-65(89-5)-12÷67-7'

Solving the bracket gives us:

'800+900×25-65(84)-12÷67-7'

Now avoiding the Bracket:

'800+900×25-5460-12÷67-7'

Now first we have to do MUltiplication, so we will get,

'800+22500-5460-12÷67-7'

Now let's do the division, so we will get,

'800+22500-5460-0.17-7'

Now lets do the additions and subtractions we will get,

<h2><u>17,832.83</u></h2>
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Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
faltersainse [42]
f(x) = \frac{x + 4}{3x^{2} + 5x - 2}

                     3x² + 5x - 2 = 0
                3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
          3x(x + 2) - 1(x + 2) = 0
                  (3x - 1)(x + 2) = 0
3x - 1 = 0       or       x + 2 = 0
    + 1 + 1                     - 2  - 2 
     3x = 1          or          x = -2
      3     3                       1     1
       x = ¹/₃         or         x = -2

      f(x) = 3x² + 5x - 2
     f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
     f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
     f(¹/₃) = ¹/₃ - ¹/₃
     f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)

      f(x) = 3x² + 5x - 2
     f(-2) = 3(-2)² + 5(-2) - 2
     f(-2) = 3(4) - 10 - 2
     f(-2) = 12 - 12
     f(-2) = 0
(x, f(x)) = (-2, 0)

    Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
      Oblique Asymptote: No Asymptotes
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3 years ago
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Given:

A figure of a circle and two secants on the circle from the outside of the circle.

To find:

The measure of angle KLM.

Solution:

According to the intersecting secant theorem, if two secant of a circle intersect each other outside the circle, then the angle formed on the intersection is half of the difference between the intercepted arcs.

Using intersecting secant theorem, we get

\angle KLM=\dfrac{1}{2}(Arc(JON)-Arc(KM))

(3x-4)=\dfrac{1}{2}(271-(x+6))

(3x-4)=\dfrac{1}{2}(271-x-6)

Multiply both sides by 2.

6x-8=265-x

Isolate the variable x.

6x+x=265+8

7x=273

Divide both sides by 7.

x=\dfrac{273}{7}

x=39

Now,

\angle KLM=(3x-4)^\circ

\angle KLM=(3(39)-4)^\circ

\angle KLM=(117-4)^\circ

\angle KLM=113^\circ

Therefore, the measure of angle KLM is 113 degrees.

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Snezhnost [94]

Answer:

A=4.

Step-by-step explanation:

Note: In the expression of area the first term should be Ax^2.

It is given that area of a rectangular floor of your house is Ax^2+5x-2 and the length is (x+2) units.

We know that, area of a rectangle is

Area=length\times width

Since length of the rectangle is (x+2), therefore (x+2) is a factor of Ax^2+5x-2 and the value of Ax^2+5x-2 is 0 at x=-2.

A(-2)^2+5(-2)-2=0

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4A-12=0

4A=12

Divide both sides by 4.

A=4

Therefore, the value of A is 4.

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