Answer:
The equation of the line is;
y + 4 = 3(x + 4)
Step-by-step explanation:
The general equation of a line is;
y = mx + b
where m is the slope and b is the y-intercept
To get the equation, let us look at the given intercepts
We have the intercepts at the point (0,5) and (-2,-1)
We have the slope of the line as follows;
m = (y2-y1)/(x2-x1) = (-1-5)/(-2-0) = -6/-2 = 3
So we have the equation as;
y = 3x + b
recall, we have the y-intercept as 5
so the complete equation is;
y = 3x + 5
Now, we can rewrite this as;
y+ 4 = 3(x + 3)
Answer:
<h2> I am not so good at drawing .</h2><h3>BE = 3.6</h3>
4x -3y + z = -10...............(1)
2x +y + 3z = 0...............(2)
-x +2y - 5z = 17...............(3)
First we multiply 3*(2) and add it to (1)
6x +3y +9z =0..................+(1)..................> 10x + 10z = -10......(4)
Then we multiply -2*(2) and add it to (3)
-4x -2y -6z =0 ...................+(3)................> -5x -11z = 17...........(5)
Multiply 2*(5) and add it to (4)
-10x -22z = 34...................+(4).................> -12 z = 24 ..............>>> z = -2
Substitute z in (4)............> 10x +10(-2) = -10.............................>>> x = 1
Substitute x and z in (2).....> 2(1) +y + 3(-2) = 0..................>>> y = 4
Solution (x,y,z) = (1,4,-2)
Well if your finding the slope and y intercept
Slope is -4
Y-int is (0,9)
So you would make the. -4 into -4/1 the you would plot (0,9) on the graph first then on the Y line go down 4 and move to the right 1
( I’m not sure if this helps)
The product of the sum of two perfect cubes:
a³ + b³ = (a + b)(a² - ab + b²)
The product of the difference of two perfect cubes:
a³ - b³ = (a - b)(a² + ab + b²)
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Remember to follow FOIL:
(b^2 + 8)(b^2 - 8)
(b^2)(b^2) = b^4
(b^2)(-8) = -8b^2
(8)(b^2) = 8b^2
(8)(-8) = -64
b^4 - 8b^2 + 8b^2 - 64
Combine like terms:
b^4 (-8b^2 + 8b^2) - 64
b^4 - 64
b^4 - 64 is your answer
hope this helps
