Find the area and circumference of the circle below: Diameter - 14 cm
2 answers:
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Yes. That point is in the solution space.
_____
You can also figure out algebraically whether the point satisfies the inequality
y < 2x + 10
Substitute the numbers
3 < 2·2 + 10
3 < 14 . . . . . . . . . . . True. (2, 3) is a solution
_____
You can also figure out algebraically whether the point satisfies the inequality
y < 2x + 10
Substitute the numbers
3 < 2·2 + 10
3 < 14 . . . . . . . . . . . True. (2, 3) is a solution
ANSWER
The general solution is , where
is an integer
<u>EXPLANATION</u>
In order to solve the linear congruence;
We need to determine the inverse of (which is a Bézout coefficient for 33).
To do that we must first use the Euclidean Algorithm to verify the existence of the inverse by showing that;
Now, here we go;
The greatest common divisor is the last remainder before the remainder of zero.
Hence, the .
We now express this gcd of 1 as a linear combination of 33 and 280.
We can achieve this by making all the non zero remainders the subject and making a backward substitution.
Equation (2) in equation (1) gives,
The above linear combination tells us that is the inverse of
.
Now we multiply both sides of our congruence relation by .
This implies that;
.
Since this is modulo, the solution is not unique because any integral addition or subtraction of the modulo (280 in this case) produces an equivalent solution.
Therefore the general solution is,
, where
is an integer
Answer:
Refer to the attached file
Hope it helps..
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