The area is 50.24 cm.
The formula is π·r^2.
The radius is 4 cm, and you square it. 16 cm.
Then you multiply 16 by 3.14 (π). And you get 50.24 cm as the area.
There are two triangles, a big triangle and a small triangle that is inside the big triangle. Because the base of the triangles are parallel to each other( indicated by the arrow), and the small triangle is perfectly inside the bigger triangle, the sides of the triangles are proportional.
It is know that the base of the small triangle is 3.5, and the hypotenuse of the small triangle is 7cm. it is also known that the the hypotenuse of the big triangle is (7+8)=15 and the base of the big triangle is unknown.
Since the triangles are proportional,
to find the base of the big triangle
base(big)/hypotenuse(big)=base(small)/hypotenuse(small)
Plug in the numbers
x/15=3.5/7
x/15=1/2
x=15/2
x=7.5
The length of the base of the big triangle is 7.5cm
Answer: f(0)=8
f(-2)=0
Step-by-step explanation:
f(0)=8+4(0)
f(0)=8+0
f(0)=8
f(-2)=8+4(-2)
f(-2)=8+(-8)
f(-2)=8-8
f(-2)=0
Answer:
the answer you are looking for is B
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
