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sertanlavr [38]
2 years ago
14

Calculate the total number of tiles needed

Mathematics
2 answers:
Ivenika [448]2 years ago
8 0
Do you have something to reference?
hram777 [196]2 years ago
6 0
What do you mean? Do you have a picture
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I’ll give thanks to those that help of course. I promise
PIT_PIT [208]

Answer: 74

Step-by-step explanation:

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3 years ago
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HELP!
spin [16.1K]
Adults pay = $33.60
Children pay = $16.80 (it's half price but if they take a round trip it's double the price. Therefore it's $16.80) then multiply both by two and add them together.

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6 0
3 years ago
A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has four identi
Tcecarenko [31]

Answer:

a. 0.1536

b. 0.9728

Step-by-step explanation:

The probability that a component fails, P(Y) = 0.2

The number of components in the system = 4

The number of components required for the subsystem to operate = 2

a. By binomial theorem, we have;

The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) is given as follows;

P(Y = 2) = \dbinom{4}{2} × 0.2² × 0.8² = 0.1536

The probability that exactly 2 last longer than 1,000 hours, P(Y = 2) = 0.1536

b. The probability that the system last longer than 1,000 hours, P(O) = The probability that no component fails + The probability that only one component fails + The probability that two component fails leaving two working

Therefore, we have;

P(O) = P(Y = 0) + P(Y = 1) + P(Y = 2)

P(Y = 0) = \dbinom{4}{0} × 0.2⁰ × 0.8⁴ = 0.4096

P(Y = 1) = \dbinom{4}{1} × 0.2¹ × 0.8³ = 0.4096

P(Y = 2) = \dbinom{4}{2} × 0.2² × 0.8² = 0.1536

∴ P(O) = 0.4096 + 0.4096 + 0.1536 = 0.9728

The probability that the subsystem operates longer than 1,000 hours = 0.9728

4 0
3 years ago
Sorry i ment to put 14/15 - 1/3 then put as a fraction in simplest form
Sergio039 [100]

Answer:

Step-by-step explanation:

14/15 - 1/3

= 6/10

In simplest form

= 3/5

7 0
3 years ago
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