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Marianna [84]
3 years ago
8

5x + 6y = -18 Write the intercep form of the equation of each line

Mathematics
1 answer:
Natalka [10]3 years ago
5 0
Y=mx+b 5x+6y= -18 6y= -5x-18 y= -5/6x-3 hope this helps
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Samira ran 3 more miles than twice the number of miles Ada ran. Which statement makes this comparison using the correct variable
const2013 [10]
2a+3=s 

I used the first letter of the name, or you can use x and y in place of a and s
7 0
3 years ago
Read 2 more answers
What is the balue of x in the proportion 2 1/4 / x= 1 1/2/3/35?
never [62]

Answer:

5 2/5

Step-by-step explanation:

(2 1/4) / x = (1 1/2) / (3 3/5)

so

x = (2 1/4) * (3 3/5) / (1 1/2)

7 0
2 years ago
Give an example of a function f : N → N that is surjective but not injective. You must explain why your example is surjective an
Helen [10]

Answer:

Consider f: N → N defined by f(0)=0 and f(n)=n-1 for all n>0.

Step-by-step explanation:

First we will prove that f is surjective. Let y∈N be any natural number. Define x as the number x=y+1. Then x∈N, and f(x)=x-1=(y+1)-1=y.  We conclude that f is surjective.

However, f is not injective. Take x1=0 and x2=1. Then x1≠x2 but f(x1)=0 and f(x2)=x2-1=1-1=0. We have shown that there are two natural numbers x1,x2 such that x1≠x2 but f(x1)=f(x2), that is, f is not injective.

Note:

If 0∉N in your definition of natural numbers, the same reasoning works with the function f: N → N defined by f(1)=1 and f(n)=n-1 for all n>1. The only difference is that you consider x1=1, x2=2 for the injectivity.

7 0
2 years ago
Which point is on the line that passes through (0,6) and is parallel to the given line? plzz helppp!
Grace [21]

Points on given line = (-12,-2) and (0,-4) because you can see them on the graph.  Then draw a parallel line thru (0,6)

To get from (0,-4) to (0,6) your x stays constant and your y coordinate increased by 10.  So your new point will do the same in relation to (-12,-2)  the x will stay constant at -12 and your y will increase by 10 to +8.  

So the answer is A (-12,8)

You can check this because parallel lines have the same slope so

y2-y1/x2-x1 should be equal for both lines.

Line 1:  -4 - (-2) / 0 - (-12) = -2/12 = -1/6

Line 2:  6 - 8 / 0 - (-12) = -2/12 = -1/6


5 0
3 years ago
What is the vertex of the absolute value function defined by ƒ(x) = |x + 5| + 7?
Temka [501]
To answer this, you need to know the general form of an absolute value function. the equation for this is f(x<span>) = </span>a|x<span> - </span>h<span>| + </span>k, and in this equation, the vertex is (h, k).

with that information, you can see that your vertex will be (-5, 7). you must take the negative for 5 because the general equation states that your h value is usually subtracted from x. to check your vertex, try plugging it into your general equation:
f(x) = a|x - (-5)| + 7
f(x) = a|x + 5| + 7 ... you see that this matches your given equation. this last part here was just to show why your 5 must be negative; your answer is bolded.
7 0
2 years ago
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