<span>Flow rate through pipe a is 0.4 m3/s
Parallel pipes have a diameter D = 30 cm => r = 15 cm = 0.15 m
Length of Pipe a = 1000m
Length of Pipe b = 2650m
Temparature = 15 degrees
Va = V / A = (0.4m3/s) / (3.14 (0.15m)^2) = 5.66 m/s
h = (f(LV^2)) / D2g
(fa(LaVa^2)) / Da2g = (fb(LbVb^2)) / Da2g and Da = Db; fa = fb
LaVa^2 = LbVb^2 => La/Lb = Vb^2/Va^2
Vd^2 = Va^2(La/Lb) => Vb = Va(La/Lb)^(1/2)
Vb = 5.66 (1000/2650)^(1/2) => 5.66 x 0.6143 = 3.4769 m/s
Vb = 3.4769 m/s
V = AVb = 3.14(0.15)^2 x 3.4769 m/s = 0.245 m^3/s</span>
Answer: The law of conservation of energy is a physical law that states energy cannot be created or destroyed but may be changed from one form to another. Another way of stating this law of chemistry is to say the total energy of an isolated system.
Explanation:
The activity occurring at an axon terminal involves the following labelled 1 - 6:
- synaptic vesicles
- synapse
- motor end plates (neurotransmitter receptor)
- calcium channel
- neurotransmitters
- axon
The transmission of nerve impulses between neurons, muscles cells or glands is known as nervous transmissions.
Axons are long slender projections of neurons which are responsible for nervous transmission.
Neurons use both electrochemical signals and chemicals known as neurotransmitters to transmit impulses from one neuron to the next.
The junction between two neurons or an effector cell is known as a synapse.
Neurotransmitters are packaged into synaptic vesicles at the axon end. When electrical signal reaches the end of the axon, influx of calcium ions through the calcium channel cause the the synaptic vessels to fuse with the presynaptic membrane and then release their contents into the synaptic cleft or space.
The neurotransmitters released then bind to the motor end plate resulting in another impulse transmission along the second neuron or an action by effector cells.
Learn more at: brainly.com/question/783627
It would have to be the right type of metal like copper to run through it
Current passes on an inductor when a voltage has been applied, reguarded as an open circuit.
30/(10+20)
=1 amperes