To show motion on a graph you draw the path of where the object has gone
Answer:
the total force vector, on test charge is points from origin to point C( 1, 1 )
Explanation:
Given the data in the question, as illustrated in the image below;
from the Image, OA = 1, OB = AC = 1
so using Pythagoras theorem
a² = b² + c²
a = √( b² + c² )
so
OC = √( OB² + AC² )
we substitute
OC = √( OA² + AC² )
OC = √( 1² + 1² )
OC = √( 1 + 1 )
OC = √2
Coordinate of C( 1, 1 )
Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )
Answer:
Speed, v = 26.5 m/s
Explanation:
It is given that,
The ball hits the ball at an angle of 40 degrees.
Initial height of the ball, h = 1 m
Vertical distance, y = 3.4 m
Horizontal distance, x = 67 m
The trajectory of the particle in projectile motion is given by :
R is the range of projectile.
Putting all the values in above equation as :
R = 71.3 meters
Now using the formula of the range of the projectile as :
Substituting the values in above equation as :
u = 26.5 m/s
So, the speed with which Fred give to the ball is 26.5 m/s. Hence, this is the required solution.
Answer:
Solution
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Given:
Mass of body = 30 kg
gravitational acceleration on the moon = 1.62 m/s
2
Weight of the body on the moon = Mass of the body×gravitational acceleration on the moon=30×1.62=48 N