The picture shows an orange falling from an orange tree
2 answers:
You might be interested in
Hello
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
, and where the negative sign means it points downwards, against the direction of the motion.
Therefore, we can use the following formula to solve the problem:
where
is the initial vertical velocity of the athlete, 
is the vertical velocity of the athlete at the maximum height (and 
at maximum height of an accelerated motion) and S is the distance covered between the initial and final moment (i.e., it is the maximum height). Re-arranging the equation, we get
This is a problem of accelerated motion, where the acceleration involved is the gravitational acceleration:
Therefore, we can use the following formula to solve the problem:
where
Answer:
Before:
After:
Explanation:
<u>Conservation of Momentum</u>
Two objects of masses m1 and m2 moving at speeds v1o and v2o respectively have a total momentum of
After the collision, they have speeds of v1f and v2f and the total momentum is
Impulse J is defined as
Where F is the average impact force and t is the time it lasted
Also, the impulse is equal to the change of momentum
As the total momentum is conserved:
We can compute the speed of the second object by solving the above equation for v2f
The given data is
a) The impulse will be computed at the very end of the answer
b) Before the collision
c) After collision
Compute the car's speed:
And the car's momentum is
The Impulse J of the system is zero because the total momentum is conserved, i.e. \Delta p=0.
We can compute the impulse for each object
The force can be computed as
The force on the car has the same magnitude and opposite sign