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Marrrta [24]
2 years ago
11

The annual average temperature of a location depends in part on its distance from the equator. The latitude at the

Mathematics
1 answer:
olasank [31]2 years ago
4 0

The meaning of the constant is the average temperature at the equator statement (A) is correct.

<h3>What is the line of best fit?</h3>

A mathematical notion called the line of the best fit connects points spread throughout a graph. It's a type of linear regression that uses scatter data to figure out the best way to define the dots' relationship.

We have a line of best fit for the data:

y = 90 - z

Here, x is measured in degrees of latitude and y is measured in degrees of Fahrenheit.

When z = 0

y = 90

Which shows the average temperature at the equator.

Thus, the meaning of the constant is the average temperature at the equator statement (A) is correct.

Learn more about the line of best fit here:

brainly.com/question/14279419

#SPJ1

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Suppose that you have 10 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards with replaceme
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Yes

Step-by-step explanation:

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Slope of (10,8) (2,1)
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Answer:

slope=7/8

Step-by-step explanation:

8-1/10-2= 7/8

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Translate to words<br> 6.4 - 3x + 8
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Eight more than three times a number subtracted from six times 4

Hope that helps and have a great day!

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Find the volume of a square pyramid with a base area of 18inch squared and the height of 4 inches
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5 0
2 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
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