Calculate the amount of HCl in grams required to react with 3.75 g of CaCO3 according to the following reaction: CaCO3(s) + 2 HC
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Answer:
The empirical formula of the organic compound is =
Explanation:
At STP, 1 mole of gas occupies 22.4 L of volume.
Moles of gas at STP occupying 2.0 L = n
Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol
Moles of gas at STP occupying 3.0 L = n'
Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol
Moles of gas at STP occupying 1.0 L = n''
Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol
Moles of carbon , hydrogen and sulfur constituent of that organic compound .
Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol
Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol
Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol
For empirical; formula divide the least number of moles from all the moles of elements.
carbon =
Hydrogen =
Sulfur =
The empirical formula of the organic compound is =