Answer:
Explanation:
Depending upon the relative arrangements of XandY X a n d Y , the square planar molecule AX3Y A X 3 Y shows only the following structure: Hence, only one structure is possible for a square planar molecule with a formula of AX3Y A X 3 Y .
Answer: Keq= [CO2]^6[H2O]^6/ [O2]^6
Explanation:
Answer:
See explanation
Explanation:
Now , we have the equation of the reaction as;
2H2S(g) + 302(g)------->2SO2(g) + 2H2O(g)
This equation shows that SO2 gas is produced in the process. Let us recall that this same SO2 gas is the anhydride of H2SO4. This means that it can dissolve in water to form H2SO4
So, when SO2 dissolve in rain droplets, then H2SO4 is formed thereby lowering the pH of rain water. This is acid rain.
Answer:
4.5moles
Explanation:
First, let us balance the equation given from the question. This is illustrated below:
KClO3 —> KCl + O2
There are 2 atoms of O on the right side and 3 atoms on the left. It can be balance by putting 2 in front of KClO3 and 3 in of O2 as shown below
2KClO3 —> KCl + 3O2
Now, we have 2 atoms each of K and Cl on the left side and 1atom each of K and Cl on the right. It can be balance by putting 2 in front of KCl as shown below:
2KClO3 —> 2KCl + 3O2
Now the equation is balanced.
From the balanced equation,
2 moles of KClO3 produced 3 moles of O2.
Therefore, 3 moles of KClO3 will produce = (3 x 3) /2 = 4.5moles of O2.
Therefore 3 moles of KClO3 will produce 4.5 moles of O2
Answer:
One of each
Explanation:
Be is in Group 2, so it loses its two valence electrons in a reaction to form Be²⁺ ions.
Carbonate ion has the formula CO₃²⁻.
We can use the criss-cross method to work out the formula of beryllium carbonate.
The steps are
Write the symbols of the anion and cation.
Criss-cross the numbers of the charges to become the subscripts of the other ion.
Write the formula with the new subscripts.
Divide the subscripts by their highest common factor.
Omit all subscripts that are 1.
When you use this method with Be²⁺ and CO₃²⁻, you might be tempted to write the formula for the beryllium carbonate as Be₂(CO₃)₂
However, you can divide the subscripts by their largest common factor (2).
This gives you the formula Be₁(CO₃)₁.
We omit subscripts that are 1, so the correct formula is
BeCO₃
There is one Be²⁺ ion and one CO₃²⁻ ion in a formula unit of beryllium carbonate.
