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Luba_88 [7]
3 years ago
9

What amounts do you compare when measuring concentration

Chemistry
1 answer:
ozzi3 years ago
7 0

Answer:

  • <em>When measuring concentration you compare </em><u>the amount of solute to the amount of solvent or solution.</u>

Explanation:

The <em>concentration</em> is a measure of how much solute is present in certain amount of solvent or solution. There are many quantitative expressions for the concentration. Some of those expressions are: percentage, molarity, molality, molar fraction, among others.

This table shows the expressions for some concentration measures, showing the amounts compared.

<u>Concentration</u>                         <u>amounts compared in form of ratio</u>

Percentage, mass/mass         (mass of solute / mass of solution) × 100  

Percentage, vol./vol.                (vol. of solue / vol. of solution) × 100

Molarity                                     (moles of solute / liters of solution)

Molality                                      (moles of solute / Kg of solvent)

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The molar mass of a solid carboxylic acid is determined by titrating a known mass of the acid with a standardized solution of Na
laiz [17]

The answer is: II.The endpoint is recorded when the solution is dark red in color rather than light pink.

The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop.  

Phenolphthalein is colorless in acidic solutions and pink in basic solutions. If  this indicator change color to dark red, more base is added and endpoint is not accurate.

If the the acid is spilled before titration, that does not make endpoint wrong and molar mass can be calculated.

In this example we can take acetic acid as carboxylic acid; basic salt sodium acetate CH₃COONa is formed from the reaction between weak acid (in this example acetic acid CH₃COOH) and strong base (in this example sodium acetate NaOH).  

Balanced chemical reaction of acetic acid and sodium hydroxide:  

CH₃COOH(aq) + NaOH(aq) → CH₃COONa(aq) + H₂O(l).  

Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base react quantitatively with each other.

8 0
3 years ago
what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

5 0
2 years ago
28.7 l of propane, c3h8, are consumed in a combustion reaction. how many grams of water are produced?
lora16 [44]
The chemical reaction would be:

C3H8 + 5O2 = 3CO2 + 4H2O

For this case, we assume that gas is ideal thus in every 1 mol the volume would be 22.41 L. We calculate as follows:

28.7 L C3H8 ( 1 mol / 22.41 L ) ( 4 mol H2O / 1 mol C3H8 ) ( 18.02 g / mol ) = 92.31 g H2O produced

Hope this answers the question.
7 0
3 years ago
How does an indicator differentiate between an acid and base?
Svet_ta [14]

Answer:

that is all I know sorry hope that may help you :)

Explanation:

Indicator is a substance which shows different colors in acidic and basic medium. Indicators can be natural (derived from natural sources) or artificial ( man-made) for example :

*Litmus is an indicator. Acid turns blue litmus into red while base turns red litmus into blue

* Turmeric solution does not show change in color (remains yellow) in acidic solution and turns red in basic solution.

8 0
1 year ago
Please help me, I really need it, God Bless you &lt;3
gladu [14]

#1

\\ \sf\longmapsto {}^{88}_{38}Sr^{2+}

  • As 2 electrons are donated Hence the No of electrons =38-2=36

#2

\\ \sf\longmapsto {}^{51}_{23}V^{3+}

  • As 3 electrons donated the no of electrons=23-3=20

#3

\\ \sf\longmapsto {}^{55}_{26}Fe^{3+}

  • No of neutrons=55-26=29

#4

\\ \sf\longmapsto {}^{112}_{48}

  • As 2 electrons are donated no of electrons =48-2=46

#5

\\ \sf\longmapsto {}^{210}_{82}Pb^{2+}

  • No of neutrons=210-82=128
7 0
2 years ago
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