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ivolga24 [154]
3 years ago
10

Which group of the Periodic Table contains element T?

Chemistry
1 answer:
Korvikt [17]3 years ago
5 0

Answer:

the 18th group or the zero group

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Which of the following statements is FALSE?A. For a given gas, the higher the temperature, the faster it will effuse.B. Particle
yanalaym [24]

Answer:

C. The larger a molecule, the faster it will effuse.

Explanation:

The sentence C "The larger a molecule, the faster it will effuse" is false because, it is the exact opposite. When a molecule is bigger it takes longer to effuse because has more components that have to pass through that effect making it last longer tan short molecules.

3 0
3 years ago
Peroxyacylnitrate (PAN) is one of the components
coldgirl [10]

C – 19,9%, H – 2,2%, N – 11,6%, O – x%

M=120\frac{g}{mol}

1 percentage

The entire molecule is 100% and all the components of the compound add up to 100%.

100% - 19,9% - 2,5% - 11,6% = 66,1%

The compound contains 66,1% oxygen.

2 molar masses

M_{C}=12,01\frac{g}{mol}

M_{H}=1,008\frac{g}{mol}

M_{O}=15,999\frac{g}{mol}

M_{N}=14,007\frac{g}{mol}

3 masses

The compound has a molar mass of 120g/mol. So one molecule weighs 120 g. To find out how much the percentage of a component weighs, you have to calculate it using the molar mass.

<u>carbon</u>

19,8% of 120g

m=120g*0,198\\m=23,76g

One molecule contains 23,76g of carbon.

<u>hydrogen</u>

2,5% of 120g

m=120g*0,025\\m=3g

One molecule contains 3g of hydrogen.

<u>oxygen</u>

66,1% of 120g

m=120g*0,661\\m=79,32g

One molecule contains 79,32g of oxygen.

<u>nitrogen</u>

11,6% of 120g

m=120g*0,0,116\\m=13,92g

One molecule contains 13,92g of nitrogen.

4 amount of substance

<u>carbon</u>

<u />n=\frac{23,76g}{12,01\frac{g}{mol} }\\n=1,98mol<u />

The compound contains about 2 moles of carbon.

<u>hydrogen</u>

n=\frac{3g}{1\frac{g}{mol} }\\n=3mol

The compound contains about 3 moles of hydrogen.

<u>oxygen</u>

n=\frac{79,32g}{15,999\frac{g}{mol} }\\n=4,96mol

The compound contains about 5 moles of oxygen.

<u>nitrogen</u>

<u />n=\frac{13,92g}{14,007\frac{g}{mol} }\\n=0,99mol<u />

The compound contains about 1 moles of nitrogen.

5. molecular formula

The formula results from the ratio of the amounts of substance.

n_{C} :n_{H} :n_{O} :n_{N} =2:3:5:1\\C_{2}H_{3}NO_{5}

8 0
3 years ago
Draw the lewis structure for butanal, which has the condensed formula ch3(ch2)2cho. show all hydrogen atoms and lone pairs of el
sergejj [24]

There are 10 hydrogen atoms that bind and there are 2 pairs of free electrons in the non-binding O atom

<h3>Further explanation</h3>

Aldehydes are alkane-derived compounds containing carbonyl groups (-CO-) where one bond binds to an alkyl group while another binds to a hydrogen atom.

The general structure is R-CHO with the molecular formula :

\large{\boxed{\boxed{\bold{C_nH_{2n}O}}}

Naming is generally the same as the alkane by replacing the suffix with -al

Butanal or butyraldehyde is an aldehyde which has 4 C atoms

Inside the structure there are 3 atoms involved in bonding:

  • 1. Atom C with 4 valence electrons, requires 4 electrons to reach the octet
  • 2. Atom O with 6 valence electrons, requires 2 electrons to reach the octet
  • 3. Atom H with 1 valence electron, requires 1 electron to reach a duplet

In describing Lewis's structure the steps that can be taken are:

  •  1. Count the number of valence electrons from atoms in a molecule
  • 2. Give each bond a pair of electrons
  • 3. The remaining electrons are given to the atomic terminal so that an octet is reached
  • 4. The remaining electrons that still exist in the central atom
  • 5. If the central atom is not yet octet, free electrons are drawn to the central atom to form double bonds

In the Butanal structure (C₄H₈O) there is 1 double bond of the functional group (-CHO) between the C atom and the O atom

<h3>Learn more: </h3>

Adding electron dots

brainly.com/question/6085185

Ionic bonding

brainly.com/question/1603987

Formal charge

brainly.com/question/7190235

 

Keywords: butanal, aldehyde, Lewis structure, a valence electron

8 0
3 years ago
Read 2 more answers
What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin
Contact [7]

<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = \frac{1}{22.4}\times 116=5.18mol of butane

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

  • <u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = \frac{8}{2}\times 5.18=20.72mol of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

  • <u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = \frac{10}{2}\times 5.18=25.9mol of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0
3 years ago
? Match the states of matter to their properties. Drag the items on the left to the correct location on the right. solids Indefi
Fantom [35]

Answer:

Solids: definite shape and definite volume (highest density)

Liquid: indefinite shape and definite volume (glide past each other)

Gas: indefinite shape and indefinite volume (lowest density)

Explanation:

look at the answer

8 0
3 years ago
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