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Anuta_ua [19.1K]
2 years ago
9

Can you please help solve and explain the steps for the calculation?

Chemistry
1 answer:
Nimfa-mama [501]2 years ago
8 0

Answer:

The hydrogen ion concentration in a solution, [H+], in mol L-1, can be calculated if the pH of the solution is known.

pH is defined as the negative logarithm (to base 10) of the hydrogen ion concentration in mol L-1 pH = -log10[H+] ...

[H+] in mol L-1 can be calculated using the equation (formula): [H+] = 10-pH

You might be interested in
Write the charge and full ground-state electron configuration of the monatomic ion most likely to be formed by each:
Maru [420]

Answer :

(a) The charge and full ground-state electron configuration of the monatomic ion is, (+1) and 1s^22s^22p^63s^23p^64s^23d^{10}4p^6

(b) The charge and full ground-state electron configuration of the monatomic ion is, (-3) and 1s^22s^22p^6

(c) The charge and full ground-state electron configuration of the monatomic ion is, (-1) and 1s^22s^22p^63s^23p^64s^23d^{10}4p^6

Explanation :

For the neutral atom, the number of protons and electrons are equal. But, they are unequal when the atoms present in the form of ions or the atom has some charges.

When an unequal number of electrons and protons then it leads to the formation of ionic species.

Ion : An ion is formed when an atom looses or gains electron.

When an atom looses electrons, it will form a positive ion known as cation.

When an atom gains electrons, it will form a negative ion known as anion.

(a) The given element is, Rb (Rubidium)

As we know that the rubidium element belongs to group 1 and the atomic number is, 37

The ground-state electron configuration of Rb is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1

This element will easily loose 1 electron and form Rb^+ ion  which attain stable noble gas electronic configuration.

The full ground-state electron configuration of Rb ion is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^6

(b) The given element is, N (Nitrogen)

As we know that the nitrogen element belongs to group 15 and the atomic number is, 7

The ground-state electron configuration of N is:

1s^22s^22p^3

This element will easily gain 3 electrons and form N^{3-} ion  which attain stable noble gas electronic configuration.

The full ground-state electron configuration of N ion is:

1s^22s^22p^6

(c) The given element is, Br (Bromine)

As we know that the bromine element belongs to group 17 and the atomic number is, 35

The ground-state electron configuration of Rb is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^5

This element will easily gain 1 electron and form Br^- ion  which attain stable noble gas electronic configuration.

The full ground-state electron configuration of Br ion is:

1s^22s^22p^63s^23p^64s^23d^{10}4p^6

4 0
3 years ago
Name each subatomic particle, its charge, and its location in an atom.
Tpy6a [65]
Protons: charge +1, have a mass of 1 and are found in the nucleus 

Neutrons: charge 0, have a mass of 1 and are found in the nucleus

Electrons: charge -1, have a mass of 1/840 and are found on the outside of the nucleus 

hope that helps 
4 0
3 years ago
The name of the following molecular compound: P203
topjm [15]
B Phosphate trioxide
5 0
3 years ago
Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.
Veronika [31]

Answer:

The answer to your question is [H₃O⁺] = 0.025   [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

-Calculate the pOH

pOH = 14 - pH

-Substitution

pOH = 14 - 1.6

-Result

pOH = 12.4

-Calculate the [OH⁻]

12.4 = -log[OH⁻]

-Simplification

[OH⁻] = antilog(-12.4)

-Result

[OH⁻] = 3.98 x 10⁻¹³

5 0
3 years ago
Should a homeowner expect more caco3 buildup in hot water pipes or cold water pipes
Arturiano [62]
Answer:
             CaCO₃ built up in hot water pipes

Explanation:

The hardness of water is classified as;

Permanent Hard Water:
                                     In this the mineral content cannot be removed by boiling. This water contains mainly following,

                                        Calcium Sulfate  CaSO₄

                                        Calcium Chloride   CaCl₂

                                        Magnesium Sulfate   MgSO₄

                                        Magnesium Chloride   MgCl₂

These salts does not precipitate out on heating water.

Temporary Hard Water:
                                     In this water the mineral content can be removed by boiling. This water contains mainly following,

                                        Calcium Bicarbonate  Ca(HCO₃)₂

                                        Calcium Carbonate  CaCO₃

                                        Magnesium Bicarbonate   Mg(HCO₃)₂

                                        Magnesium Carbonate  MgCO₃

These salts does not precipitate out on heating water. i.e.

                Ca(HCO₃)₂    -------heat------>    CaCO₃  +  CO₂  +  H₂O

The CaCO₃ are formed in the form of scales.

Result:
           Hence, we can say that that CaCO₃ built up in hot water pipes.
5 0
3 years ago
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