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Alexeev081 [22]
3 years ago
9

What is observed when a solution of potassium iodide is added to silver nitrate solution ? a) No reaction takes place (b) White

precipitate of silver iodide is formed (c) yellow precipitate of Agl is formed (d) Agl is soluble in water.
Chemistry
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

c) yellow precipitate of Agl is formed

Explanation:

KI + AgNO3 = AgI (s)+ KNO3

c) yellow precipitate of Agl is formed

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10. Write the formula for the compounds: copper (1) chloride and copper (II) chloride
Natali [406]

Answer:

Copper(II) chloride (CuCl2) reacts with several metals to produce copper metal or copper(I) chloride (CuCl) with oxidation of the other metal.

Explanation:

3 0
3 years ago
What are the main reactants and products in a neutralization reaction?
blagie [28]

The reactants in the neutralization reaction are an acid and a base while the products are a salt and water.

7 0
3 years ago
How many molecules of CBr4 are in 250 grams of CBr4
Kazeer [188]

Answer:- 4.54*10^2^3 molecules.

Solution:- The grams of tetrabromomethane are given and it asks to calculate the number of molecules.

It is a two step unit conversion problem. In the first step, grams are converted to moles on dividing the grams by molar mass.

In second step, the moles are converted to molecules on multiplying by Avogadro number.

Molar mass of CBr_4  = 12+4(79.9)  = 331.6 g per mol

let's make the set up using dimensional analysis:

250g(\frac{1mol}{331.6g})(\frac{6.022*10^2^3molecules}{1mol})

= 4.54*10^2^3 molecules

So, there will be 4.54*10^2^3 molecules in 250 grams of CBr_4 .


8 0
3 years ago
What is the mole fraction of cation in 1M of aluminium sulphate​
Svetllana [295]

The mole fraction of cation (Al)=0.4

<h3>Further explanation</h3>

Given

1 M of Aluminium sulphate​

Required

The mole fraction of cation

Solution

Ionization of the Aluminum sulfate solution( assume 1 L solution ) :

mol Al₂(SO₄)₃ = M x V = 1 M x 1 L = 1 mol

Al₂(SO₄)₃⇒2Al³⁺ + 3SO₄²⁻

1 mol          2 mol   3 mol

From this equation, total mol in solution = 2+3 = 5 moles

Mol fraction Al(as a cation) :

= 2/5=0.4

8 0
3 years ago
Which pair of elements will form an ionic bond?
dimulka [17.4K]
<span>Li, Cl
and
</span><span> I, Na
</span>hope this help 

5 0
3 years ago
Read 2 more answers
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