Which of the following compounds is a gas at room temperature? A : CH3CH2OH B : CH3CH2CH2CH2CH2CH2CH3 C : CH3CH2CH3 D : HOCH2CH2
1 answer:
Answer:
C.
Explanation:
Molecules with the stronger intermolecular forces are pulled tightly together to form solid at higher temperatures and that's why the freezing point is higher.
Also, molecules with the stronger intermolecular force have greater interaction between the molecules and thus on heating do not boil easily and have high boiling point also.
Thus, melting point and boiling point increases with increase in number of carbon atoms and also increase in intermolecular forces (like hydrogen bonding, if present).
Thus, the compound which is gas at room temperature is <u>because it has least number of carbon atoms and absence of hydrogen bonding.</u>
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Answer:
C. will precipitate out first
the percentage of remaining = 12.86%
Explanation:
Given that:
A solution contains:
From the list of options , Let find the dissociation of
where;
Solubility product constant Ksp of is
Thus;
replacing the known values in order to determine the unknown ; we have :
The dissociation of
The solubility product constant of is
The dissociation of is :
Thus;
Thus; the phosphate anion needed for precipitation is smaller i.e in
than in
Therefore:
will precipitate out first
To determine the concentration of when the second cation starts to precipitate ; we have :
This implies that when the second cation starts to precipitate ; the concentration of in the solution is 0.00566
Therefore;
the percentage of remaining = concentration remaining/initial concentration × 100%
the percentage of remaining = 0.00566/0.0440 × 100%
the percentage of remaining = 0.1286 × 100%
the percentage of remaining = 12.86%