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Kay [80]
2 years ago
15

What’s the answer to this problem , figure out the area and perimeter of this triangle

Mathematics
1 answer:
Zigmanuir [339]2 years ago
4 0

Answer:

                Area = 67.5 m²

        Perimeter = 69 m

Step-by-step explanation:

<h3>Area of triangle:</h3>

   b = 27 m  & h = 5 m

     \sf \boxed{\text{\bf Area of triangle =$\dfrac{1}{2}bh$}}

                                   \sf = \dfrac{1}{2}*27*5\\\\     =\dfrac{135}{2}\\\\= 67.5 \ m^2

<h3>Perimeter of triangle:</h3>

       Perimeter = sum of all sides

                         = 27 + 34 + 8

                         = 69 m

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Consider the following information related to a set of quantitative sample data:
svlad2 [7]

Answer:

(a) There are outliers

(b) x and x >62

Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

q_0 = -24

q_1 = 14.5

q_2 = 24.5

q_3 = 33.5

q_4 = 64

Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

IQR = Q_3 - Q_1

So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

Lower = -14

The upper bound of outlier becomes

Upper = Q_3 +(1.5 * IQR)

Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

Upper = 62

So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

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