For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
first one is A and the second one is B.
Step-by-step explanation:
Out of what? Nothing is shown. :(
Answer:
x = 10
Step-by-step explanation:
We know that the sum of angles in a triangle is equal to 180 degrees;
This means that
71+50+(6x-1) = 180; now that you have an algebraic expression, you can solve for x.
71+49+6x=180
120+6x = 180
6x = 60
x = 10
Answer:
12
Step-by-step explanation:
sum of all angles of triangle =180
3x-12+2x+11x=180
16x-12=180
16x=192
x=12
