2.At the end of a school

In a triangle the measure of the first angle is twice the measure of the second angle. the measure of the third angle is 8 degre

Rufina [12.5K]

Let's call the missing angles Q, R, and S. We know that Q = 2R and S = R - 8 and we also know that Q + R + S = 180. So that really just means that 180 = 4R - 8 Add 8 on both sides of the equal sign
188 = 4R So we divide on both sides of the equal sign by 4
47 = R And that means that Q = 2 * 47 So Q = 94 and S = 47 - 8 So S = 39
39 + 94 + 47 = 180
The missing angles are 39 degrees 94 degrees and 47 degrees.

4 0

3 years ago

If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?

Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is $2 x^{3} + 4 x^{2} -30x$ .

Step-by-step explanation:

The given is,

$2 x^{3} + 4 x^{2} -30x$ ................................(1)

Step:1

Check for option A,

x = 1, dimensions 8 by 9 by 1

From the equation (1),

Volume = $2 (1^{3}) + 4 (1^{2} )-30(1)$

$=2+4-30$ = -24...................(2)

From the dimensions,

Volume = ( 8 × 9 × 1 )

= 72............................................(3)

From equation (2) and (3)

-24 ≠ 72

So, X=1; dimensions 8 by 9 by 1 is not possible.

Check for option B,

x = 1, dimensions 2 by 5 by 3

From the equation (1),

Volume = $2 (1^{3}) + 4 (1^{2} )-30(1)$

$=2+4-30$ = -24...................(4)

From the dimensions,

Volume = ( 2 × 5 × 3 )

= 30.........................................(5)

From equation (4) and (5)

-24 ≠ 30

So, X=1; dimensions 2 by 5 by 3 is not possible.

Check for option C,

x = 4, dimensions 2 by 5 by 3

From the equation (1),

Volume = $2 (4^{3}) + 4 (4^{2} )-30(4)$

$=2(64)+4(16)-30(4)$

$= 128+64-120$

= 72.............................................(6)

From the dimensions,

Volume = ( 2 × 5 × 3 )

= 30............................................(7)

From equation (6) and (7)

72 ≠ 30

So, X=4; dimensions 2 by 5 by 3 is not possible.

Check for option C,

x = 4, dimensions 8 by 9 by 1

From the equation (1),

Volume = $2 (4^{3}) + 4 (4^{2} )-30(4)$

$=2(64)+4(16)-30(4)$

$= 128+64-120$

= 72............................................(8)

From the dimensions,

Volume = ( 8 × 9 × 1 )

= 72............................................(9)

From equation (8) and (9)

72 = 72

So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is $2 x^{3} + 4 x^{2} -30x$ .

4 0

3 years ago

Given the function f(x) = -0.5|2x + 2| + 1, for what<br> values of x is f(x) = 6?

Licemer1 [7]

Answer:

<em>No values of x can make f(x)=6</em>

Step-by-step explanation:

Equation with Absolute Value

The absolute value of a number is always positive. That condition must be met when solving equations. Any condition that goes against the rule, must be discarded and not part of the solution.

The function provided in the question is:

$f(x) = -0.5|2x + 2| + 1$

We need to find the value(s) of x that make:

f(x)=6

It needs to solve the equation:

$-0.5|2x + 2| + 1=6$

Subtracting 1:

$-0.5|2x + 2| =6-1=5$

Dividing by -0.5:

$|2x + 2| =5/(-0.5)=-10$

We reach to this equation to solve:

$|2x + 2| =-10$

As stated above, the absolute value is always positive, and the equation forces the absolute value to be negative. There is no possible value of x that makes the absolute value negative, thus:

No values of x can make f(x)=6

6 0

3 years ago

Sort these in either Combination or Permutation PLEASE HELP!!!! 100 POINTS

balandron [24]

A permutation is where there is a difference in positions where the things will be selected into (order matters). Combination is where order doesn’t matter. I have sorted them but I am not sure about the starting line up one. If the players are selected into specific positions then it would be a permutation.

3 0

2 years ago

Read 2 more answers

Please help due today!!!!!!!:(

Alchen [17]

Answer:

D

Step-by-step explanation:

∠AXD = 180°

∠AXB = 32°

so you do 180 - 32 and you get 148. hope I helped:)

8 0

2 years ago