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kupik [55]
2 years ago
11

Which statement correctly pairs the climate factor with its effect on temperature? *

Chemistry
1 answer:
allochka39001 [22]2 years ago
5 0

Answer:

A region on top of a mountain is cooler than at the base.

Explanation:

Pressure and temperature have direct relationship with each other. With the decrease in pressure, the temperature decreases and vice versa. When the air rises in the atmosphere, the pressure starts to fall. The low pressure at the peak of the mountains tends to cause the fall in temperature. It is because of this reason that it is cooler at the top of the mountain while the temperature is less cool in the foothills.

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What is the chemical reaction between an acid and a base which results in the formation of salt and water?
Tcecarenko [31]
Neutralization is the process in which anacid and base react to give salt and water

7 0
4 years ago
Calculate the volume of a 3.50 M solution of H2SO4 made from 49 g of H2SO4
maxonik [38]

Answer:

0.143L

Explanation:

Molar mass of H2SO4 = 98g/Mol

No of mole = mass/molar mass

No of mole= 49/98 = 0.5 mol

No of mol = concentration × volume

Volume = n/C = 0.5/3.5 = 0.143L

3 0
3 years ago
The value of the entropy change for the process N₂ (g) + 3H₂ (g) --> 2NH₃ (g) is ________.
kodGreya [7K]

Answer:

negative

Explanation:

Entropy is a measure of the "disorder" in a system.

In this reaction, the amount of disorder decreases. This is because one gas molecule (NH₃) has more order than two gas molecules (N₂ and H₂). Therefore, the entropy change should be negative.

5 0
2 years ago
A hot object will have ___ kinetic energy
Masja [62]

Answer:

More/ Alot? I think is what you are looking for?

Explanation:

It will definitely have some but I'm not sure on what word you are looking for.

6 0
3 years ago
Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
 K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
 pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>
6 0
3 years ago
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