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jarptica [38.1K]
2 years ago
9

Identify parts A-E on the following energy diagram.

Chemistry
1 answer:
Elena L [17]2 years ago
8 0

Answer:

See below

Explanation:

A  Reactants

B  Activation energy

C  transition state

D  enthalpy change

E   products

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nirvana33 [79]

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A salt and water (H2O)

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What is an example of a chemical bond
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Sodium Chloride or NaCl is a ionic bond
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What is the frequency of electromagnetic radiation with a wavelength of 6.34 x 10^8 m?
Svetllana [295]
<h2>Answer: 4.72 × 10⁷  s⁻¹ or Hz</h2><h3>  Explanation: </h3>

frequency = speed of light ÷ wavelength

frequency = (2.99 × 10⁸  m/s)  ÷  (6.34 × 10⁸  m)

                  =  4.72 × 10⁷  s⁻¹ or Hz

8 0
3 years ago
Calculate the root mean square velocity of nitrogen molecules at 25°c. a) 729 m/s b) 515 m/s c) 149 m/s d) 297 m/s
Elena L [17]

Answer:

root mean square velocity of nitrogen at 25°c is 515 m/s

correct option is b) 515 m/s

Explanation:

given data

temperature = 25°c = 25 + 273 = 298 K

to find out

root mean square velocity of nitrogen molecules

solution

we know that root mean square velocity of gas is Vrms = \sqrt{\frac{3RT}{M}}      .......................1

mass of gas = M

universal gas constant = R

temperature = T

and we know mass of nitrogen = 28 g = 28 × 10^{-3} kg

Vrms = \sqrt{\frac{3RT}{M}}

Vrms = \sqrt{\frac{3(8.314)298}{28*10^{-3}}}

Vrms = 515.22 m/s

root mean square velocity of nitrogen at 25°c is 515 m/s

correct option is b) 515 m/s

3 0
3 years ago
Calculate the silver ion concentration in a saturated solution of silver(I) sulfate (K sp = 1.4 × 10 –5). 1.5 × 10–2 M 1.4 × 10–
spin [16.1K]

Answer:

3.0x10⁻²M

Explanation:

Silver sulfate, Ag₂SO₄, has a product constant solubility equilbrium of:

Ag₂SO₄(s) ⇄ 2Ag⁺ + SO₄²⁻

When an excess of silver sulfate is added, some Ag₂SO₄ will react producing Ag⁺ and SO₄²⁻ until reach the equilbrium determined for the formula:

ksp = 1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

Assuming the Ag₂SO₄ that react until reach equilibrium is X, we can replace in Ksp expression:

1.4x10⁻⁵ = [Ag⁺]² [SO₄²⁻]

1.4x10⁻⁵ = [2X]² [X]

1.4x10⁻⁵ = 4X³

3.5x10⁻⁶ = X³

0.015 = X

As [Ag⁺] is 2X:

[Ag⁺] = 0.030 = 3.0x10⁻²M

The answer is:

<h3>3.0x10⁻²M</h3>
7 0
3 years ago
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