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A 50.0 mL solution of 0.133 M KOH is titrated with 0.266 M HCl . Calculate the pH of the solution after the addition of each of

shtirl [24]

Answer:Calculate The PH Of The Solution After The Addition Of The Following Amounts Of HCl. PLEASE HELP! SHOW ALL STEPS!! This problem has been solved!

Explanation:

4 0

2 years ago

Farmers who raise cotton once used arsenic acid, H3AsO4, as a defoliant at harvest time. Arsenic acid is a polyprotic acid with

Bess [88]

Answer:

pH = 1.95

Explanation:

For polyprotic acids, it is generally assumed that all H⁺ comes from the 1st ionization step. The amount of H⁺ delivered into solution for the 2nd and 3rd ionization steps are in the order of 10⁻⁴M and 10⁻⁶M respectively and provide very little change in pH from the quantity delivered in the 1st ionization step.

Therefore... the [H⁺] concentraion and pH are computed as follows...

[H⁺] = √Ka₁[H₃AsO₄] = √(2.5 x 10⁻⁴)(0.500) M = 0.1118M

pH = -log[H⁺] = -log(0.01118) = 1.95

8 0

2 years ago

What is the mass of silver chlorate (191.32 g/mol) that decomposes to release 0.466L of oxygen gas at STP? AgC1036) _AgCl). _026

vesna_86 [32]

Answer : The mass of silver chlorate will be 2.654 grams.

Explanation :

The balanced chemical reaction is,

$2AgClO_3\rightarrow 2AgCl+3O_2$

First we have to calculate the moles of oxygen gas at STP.

As, 22.4 L volume of oxygen gas present in 1 mole of oxygen gas

So, 0.466 L volume of oxygen gas present in $\frac{0.466}{22.4}=0.0208$ mole of oxygen gas

Now we have to calculate the moles of silver chlorate.

From the balanced chemical reaction, we conclude that

As, 3 moles of oxygen produced from 2 moles of silver chlorate

So, 0.0208 moles of oxygen produced from $\frac{2}{3}\times 0.0208=0.01387$ moles of silver chlorate

Now we have to calculate the mass of silver chlorate.

$\text{Mass of }AgClO_3=\text{Moles of }AgClO_3\times \text{Molar mass of }AgClO_3$

Molar mass of silver chlorate = 191.32 g/mole

$\text{Mass of }AgClO_3=0.01387mole\times 191.32g/mole=2.654g$

Therefore, the mass of silver chlorate will be 2.654 grams.

3 0

2 years ago

Help me pls rawr uwu SSUsSY

cricket20 [7]

Help 2 what the answer for this?

7 0

2 years ago

Read 2 more answers

A polar covalent bond will form between which two atoms?

Alex_Xolod [135]

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

Less than 0.4 then it is Non Polar Covalent

Between 0.4 and 1.7 then it is Polar Covalent

Greater than 1.7 then it is Ionic

For Be and F,

E.N of Fluorine = 3.98

E.N of Beryllium = 1.57

________

E.N Difference 2.41 (Ionic Bond)

For H and Cl,

E.N of Chorine = 3.16

E.N of Hydrogen = 2.20

________

E.N Difference 0.96 (Polar Covalent Bond)

For Na and O,

E.N of Oxygen = 3.44

E.N of Sodium = 0.93

________

E.N Difference 2.51 (Ionic Bond)

For F and F,

E.N of Fluorine = 3.98

________

E.N Difference 0.00 (Non-Polar Covalent Bond)

Result:

A polar covalent bond is formed between Hydrogen and Chlorine atoms.

5 0

3 years ago