Is it possible to add an atom with 12 protons and 13 electrons explain
1 answer:
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Answer:
Rate constant of the reaction is .
Explanation:
A + B + C → D + E
Let the balanced reaction be ;
aA + bB + cC → dD + eE
Expression of rate law of the reaction will be written as:
Rate(R) of the reaction in trail 1 ,when :
...[1]
Rate(R) of the reaction in trail 2 ,when :
...[2]
Rate(R) of the reaction in trail 3 ,when :
...[3]
Rate(R) of the reaction in trail 4 ,when :
...[4]
By [1] ÷ [2], we get value of c ;
c = 1
By [3] ÷ [4], we get value of b ;
b = 0
By [2] ÷ [3], we get value of a ;
a = 2
Rate law of reaction is :
Rate constant of the reaction = k
Answer:
A) 10.75 is the concentration of arsenic in the sample in parts per billion .
B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.
C) It will take 1.37 years to remove all of the arsenic from the lake.
Explanation:
A) Mass of arsenic in lake water sample = 164.5 ng
The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.
To calculate the ppm of oxygen in sea water, we use the equation:
Both the masses are in grams.
We are given:
Mass of arsenic = 164.5 ng =
Volume of the sample = V =
Density of the lake water sample ,d=
Mass of sample = M =
10.75 is the concentration of arsenic in the sample in parts per billion.
B)
Mass of arsenic in of lake water =
Mass of arsenic in lake water be m.
Mass of arsenic in lake water :
1 g = 0.001 kg
7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg
7,633.66 kg the total mass of arsenic in the lake that the company have to remove.
C)
Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.
Days required to remove 1 kilogram of arsenic from the lake water :
Then days required to remove 7,633.66 kg of arsenic from the lake water :
1 year = 365 days
499.19 days =
It will take 1.37 years to remove all of the arsenic from the lake.