<h3><u>Answer;</u></h3>
3.4 kJ
<h3><u>Explanation</u>;</h3>
Taking the mass of water as 10.0 g
Moles of water = Mass /molar mass
Moles of water in 10.0 g;
= 10g H2O x 1mol/18g
=0.56mol
But, 1 mole of water = 6.01 kJ
Hence;
6.01kJ/1mol H2O= x kJ/.56mol,
x = <u>3.4kJ</u>
seaweed having 50 g salt in 1 L water. The bucket contains 150 g of salt in 2 L of water
amount of water present in bucket is twice to amount of water in weed

At equilibrium, volume of water in weed is x and volume in bucket is y but concentration remain same as follows:

At equilibrium, weed loose z L from 1 L water to bucket containing 2 L as follows:

Thus, Weed will loose 0.25 L of water
Answer:
Reduced species and oxidizing agent: sulfur in the form of sulfate.
Oxidized species and reducing agent: chromium in the form of chromous hydroxide.
Explanation:
Hello!
In this case, for the reaction:

We can see that the oxidation states of sulfur and chromium change from +6 to +4 and +3 to +6 respectively; in such a way, since the oxidized species is the same reducing agent because it undergoes an increase in the oxidation state, we infer that chromium is it as it goes from +3 to +6.
Moreover, since the reduced species is the same oxidizing agent because it undergoes a decrease in the oxidation state, we infer that sulfur is it as it goes from +6 to +4.
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Yes, because beryllium is less dense and harder than oxygen.