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2 years ago

PLEASEEEEEEEEEEEEE HELP

Mathematics

1 answer:

Pavel [41]2 years ago

7 0

Step-by-step explanation:

(f-g)(4)

=f(4)-g(4)

=3x-3-(3x-4)

=3x-3-3x+4

hope it helps you

You might be interested in

Solutions of x2 + 13x + 30 = 0 by factoring.

VMariaS [17]

Answer:

x = -10 or x = -3

Step-by-step explanation:

Here, the given equation is

$x^{2} + 13x + 30 = 0$

The given equation can be solved by the method of SPLITTING THE MIDDLE TERM

Split 13 in such a way that sum of the terms = 13

and product of the terms = 30

So, the given equation becomes $x^{2} + 10x + 3x + 30 = 0$

Here, 10x+ 3x = 13x and 10 x 3 = 30

Now, simplifying the equation,

$x(x+10) + 3(x + 10) = 0 \\(x+3) (x+10) =0$

⇒ either (x+ 10) = 0 ,or (x+ 3) = 0

⇒ x = -10 or x = -3

4 0

3 years ago

Consider a population list x with μx=10 and SDx = 1. A second population list, y, with μy=10 and SDy=2, is added to the first li

Basile [38]

Answer:

The combined standard deviation is 1.58114.

Step-by-step explanation:

The formula to compute the combined standard deviations of two different data sets is:

$SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}$

Here $\mu_{c}$ is the combined mean given by:

$\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}$

It is provided that the sample size is same for both the data sets, i.e. $n_{X} = n_{Y}=n$

Compute the combined mean as follows:

$\mu_{c}=\frac{n_{X}\mu_{X}+n_{Y}\mu_{Y}}{n_{X}+n_{Y}}\\=\frac{(n\times10)+(n\times10)}{n+n}}\\=\frac{20n}{2n}\\ =10$

Compute the combined standard deviation as follows:

$SD_{c} =\sqrt{\frac{n_{X}S^{2}_{X}+n_{2}S^{2}_{Y}+n_{X}(\mu_{X}-\mu_{c})^{2}+n_{Y}(\mu_{Y}-\mu_{c})^{2}}{n_{X}+n_{Y}}}\\=\sqrt{\frac{(n\times1^{2})+(n\times2^{2})+(n(10-10))+(n(10-10))}{n+n}}\\=\sqrt{\frac{n+4n}{2n} } \\=\sqrt{\frac{5n}{2n} } \\=\sqrt{\frac{5}{2}} \\=1.58114$

Thus, the combined standard deviation is 1.58114.

3 0

3 years ago

Let f(x) = 8x^3 − 22x^2 − 4 and g(x) = 4x − 3. Find f(x) over g(x).

Alenkasestr [34]

You would use the long division technique..

Here it looks like:

 --------------------
4x − 3 | 8x^3 − 22x^2 − 4
---------
 |
 |
 |

and like that,,,

after you do this, you will get

$2x^2-4x-3-\frac{13}{4x-3}$

hope that helps

5 0

3 years ago

The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to det

Maru [420]

Answer:

0.077994

Step-by-step explanation:

Given that the owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club.

$H_0: Mean = 30\\H_a: Mean >30$

(Right tailed test)

Sample size = $n=250$

Sample mean = 30.45

Mean difference = $30.45-30=0.45\\$

Sample std dev s = 5

Sample std error = $\frac{5}{\sqrt{n} } =\frac{5}{\sqrt{250} } \\=0.3163$

Test statistic = Mean diff/std error = $=\frac{0.45}{0.3163} =1.423$

Since population std deviation is not know we use t test

p value = $0.077994$

4 0

3 years ago

Larry earns $11.25/hour selling televisions. He also earns 4.5% commission on his sales. What is his

monitta

Answer:

C) $573.75

Step-by-step explanation:

We can come up with the equation of this Gross Weekly pay as:

$P(t)=11.25t+0.045S$

Where P is the amount Larry will get paid, t is the time worked and S is the amount of sales he generated that week. This was derived from the fact that 11.25 is the slope and 0.045S is the y-intercept. By plugging in those values we have:

$P(35)=11.25(35)+0.045(4000)=573.75$

C) $573.75

4 0

3 years ago