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1 year ago

For which value of a does Limit of g(x) as x approaches alpha not exist?

Mathematics

1 answer:

Hunter-Best [27]1 year ago

7 0

The value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

<h3>Limit of a function</h3>

The limit of a function is the limit of a function as x tends to a value.

From the given graph, you can see that the function g(x) goes large at the point where the arrows orange and purple point down from the x-coordinates -1 and 1.

Hence the value of a where the Limit of g(x) as x approaches alpha not exist are -1 and 1

Learn more on limit of a function here: brainly.com/question/23935467

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An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn

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The first four terms are : 15000, 14850, 14700, 14550
a = 15000 ; d = -150
The explicit formula is : $a_{n} = - 150n \: + 15150$

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

$a_{n} \: = nd \: + c$

For n = 1

$15000 = 1( - 150) + c$

$15000 = - 150 + c$

$c = 15150$

Hence, the explicit formula for the nth term is :

$a_{n} \: = - 150n \: + 15150$

Learn more : brainly.com/question/12006170

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For which value of a does Limit of g(x) as x approaches alpha not exist?​

For which value of a does Limit of g(x) as x approaches alpha not exist?