2 years ago

0 divided by 0 help me plz

Mathematics

1 answer:

marusya05 [52]2 years ago

8 0

Answer:

Step-by-step explanation:

Its basically infinite because 9 divided by 3 is how many times 3 goes into 9 so 0 divided by 0 is how many times 0 goes into 0 which is infinite.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

The correct equation is

$y+1=\sqrt{-2y-3}$

Solve for y

squared both sides

$(y+1)^2=(-2y-3)$

$(y^2+2y+1)=(-2y-3)$

$y^2+2y+1+2y+3=0$

$y^2+4y+4=0$

$(y+2)(y+2)=0$

$y=-2$

Verify

substitute the value of y in the original expression

$-2+1=\sqrt{-2(-2)-3}$

$-1=1$ ----> is not true

therefore

There are no true solutions to the equation.

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