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Neko [114]
2 years ago
12

Digital information can be sent through the vacuum if space, but the information must be-. A. below a certain size. B. converted

to wave pulses C. encrypted for security reasons. D.sent in only one direction​
Physics
1 answer:
blsea [12.9K]2 years ago
8 0

Digital information can be sent through the vacuum if space, but the information must be converted to wave pulses. The correct option is B.

<h3>What is digital information?</h3>

The digital information consists of data generated by the electrical systems. For examples, computers, screens, scientific calculators or any communication devices.

The electromagnetic waves do not require medium, So, they can travel through vacuum. So, Digital information can be sent through the vacuum or space.

Therefore, the correct option is B.

Learn more about digital information.

brainly.com/question/4507942

#SPJ1

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A uniform meterstick in static rotational equilibrium when a mass of 220 g is suspended from the 5.0 cm mark, a mass of 120 g is
KatRina [158]

Answer:

m = 170 g

Explanation:

Meter stick is suspended at 40 cm mark

So here the torque due to additional mass and torque due to weight of the spring must be counter balanced

given that

1) 220 g is suspended at x = 5 cm

2) 120 g is suspended at x = 90 cm

3) mass of the scale is acting at its mid point i.e. x = 50 cm

now with respect to the suspension point the torque must be balanced

so we have

220(40 - 5) = m(50 - 40) + 120(90 - 40)

220(35) = 10 m + 6000

by solving above equation we have

m = 170 g

7 0
3 years ago
Observing neutrinos from the Sun is an important way to check the fusion rate, but it can be very tough to build a machine that
Vika [28.1K]

Answer:

The trouble that the most recent experiment, Borexino, have to overcome was that

neutrinos hardly interact with matter and so radioactive decay of ant material inside the detector could look exactly like a neutrino interaction too

5 0
3 years ago
A comet of mass 1.20 × 10¹⁰kg moves in an elliptical orbit around the Sun. Its distance from the Sun ranges between 0.500 AU and
irina [24]

The eccentricity of its orbit is $$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

<h3>What is mass?</h3>
  • Mass is a physical body's total amount of matter. It also serves as a gauge for the body's inertia or resistance to acceleration (change in velocity) in the presence of a net force. The strength of an object's gravitational pull to other bodies is also influenced by its mass.
  • The kilogram is the SI unit of mass (kg). In science and technology, a body's weight in a given reference frame is the force that causes it to accelerate at a rate equal to the local acceleration of free fall in that frame.
  • For instance, a kilogram mass weighs around 2.2 pounds at the surface of the planet. However, the same kilogram mass would weigh just about 0.8 pounds on Mars and about 5.5 pounds on Jupiter.
  • An object's mass is a crucial indicator of how much stuff it contains. Weight is a measurement of an object's gravitational pull. It is influenced by the object's location in addition to its mass. As a result, weight is a measurement of force.

The length of the semi-major axis is calculated as follows:

where, $G=6.67 \times 10^{-1} \mathrm{~m}^3 / \mathrm{kgs}$

$M=1.99 \times 10^{30} \mathrm{~kg}=$mass of sur

$m=1.20 \times 10^{10} \mathrm{~kg}$ - a mass of the comet

$$\begin{aligned}\therefore \quad \text { At aphelion, } r &=50 \times U \\&=50 \times 1.496 \times 10^{11} \mathrm{~m} . \\U=-\frac{6.67 \times 10^{-11} \times \mathrm{m} 1.99 \times 10^{30} \times 1.20 \times 10^{10}}{50 \times 1.496 \times 10^{11}} \\U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

$$U=-2.13 \times 10^{17} \mathrm{~J} .\end{aligned}$$

To learn more about mass, refer to:

brainly.com/question/3187640

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4 0
2 years ago
Is oxygen a reactant or product
dezoksy [38]

Answer:

Methane and oxygen (oxygen is a diatomic — two-atom — element) are the reactants, while carbon dioxide and water are the products

Explanation:

3 0
3 years ago
Read 2 more answers
The temperature of 10 kg of a substance rises by 55oC when heated. Calculate the
guajiro [1.7K]

Given :

The temperature of 10 kg of a substance rises by 55oC when heated.

To Find :

The  temperature rise when 22 kg of the substance is heated with the same quantity of heat.

Solution :

We know, change in temperature when heat is given to object is given by :

\Delta H = m S\Delta T

It is given that same amount of heat is given in both the cases also the substance is same.

So,

M_1 S \Delta T_1 = M_2 S \Delta T_2\\\\10\times 55 = 22 \times \Delta T_2\\\\\Delta T_2 = 25^o\ C

Hence, this is the required solution.

7 0
3 years ago
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